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Gelneren [198K]
3 years ago
8

Simplify. 14.8 + 6.25 + 0.97

Mathematics
2 answers:
lara [203]3 years ago
8 0

Answer:

22.02

Step-by-step explanation:

Natali5045456 [20]3 years ago
4 0

Answer: 22.02

Step-by-step explanation:

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Question 5
Maksim231197 [3]
BBBBBBBBBBBBBBBBBBBBBBBB
8 0
3 years ago
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0
3 years ago
State the commutative property of addition using the variables a and b.
Verdich [7]

Answer:

a+b=b+a

Step-by-step explanation:

so 7+4=12 and 4+7=12 so addition is commutative

7 0
3 years ago
Read 2 more answers
7. Virus growth is an example of which type of function?
Karolina [17]

Answer:

Since many viruses can infect a large number of different cell types, ... An example is potato yellow dwarf virus, which can grow in leafhoppers

5 0
3 years ago
Qual o valor da soma dos monômios 10xm - 8mx + 6xm - 13xm?
soldi70 [24.7K]

Answer:

The value of given expression = - 5mx

Step-by-step explanation:

Given expression;

10xm - 8mx + 6xm - 13xm

Find:

The value of given expression

Computation:

⇒ 10xm - 8mx + 6xm - 13xm

Step 1 ;

Rearrange expression;

⇒ 10mx - 8mx + 6mx - 13mx

Step 2 ;

Adding all terms

⇒ 10mx + 6mx - 8mx - 13mx

Step 3 :

Subtract term

⇒ 16mx - 21mx

⇒ -5mx

The value of given expression = - 5mx

8 0
3 years ago
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