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zysi [14]
3 years ago
14

Please help asap 50 pts

Mathematics
1 answer:
grigory [225]3 years ago
5 0
|-1/5| < |-1/3| < |-7|

Your answer:

B. y = -1/5 x^2; y = -1/3 x^2; y = -7x^2

Look at the picture.

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Can you write all of those in Fractions Decimals and Percentages .
Misha Larkins [42]

Answer:

a) decimal 7.222

fraction: 65/9

percentage: 722.22

b) Fraction: 37/5

decimal: 7.4

Percentage: 740

Step-by-step explanation:

6 0
3 years ago
(6 - 1) + (3m)i = -12 + 27i
Yanka [14]

Answer:

We want to solve the equation:

(6 - 1) + (3m)i = -12 + 27i

Where m is a complex number.

first, we can rewrite this as:

5 + 3*m*i = -12 + 27*i

3*m*i = -12 - 5 + 27*i

3*m*i = -17 + 27*i

And we can write m as:

m = a + b*i

Replacing that in the above equation we get:

3*(a + b*i)*i = -17 + 27*i

3*a*i + 3*b*i^2 = -17 + 27*i

and we know that i^2 = -1

3*a*i - 3*b = -17 + 27*i

The real part in the left (-3*b) must be equal to the real part in the right (-17)

then:

-3*b = -17

b = -17/-3 = 17/3

And the imaginary part in the left (3*a) must be equal to the imaginary part in the right (27)

then:

3*a = 27

a = 27/3.

Then the value of m is:

m = a + b*i = (27/3)  + (17/3)*i

8 0
3 years ago
A survey of several 8 to 9 year olds recorded the following amounts spent on a trip to the mall: $31.11,$25.01,$18.53,$14.37,$24
Alex17521 [72]

Solution :

Amounts spent on a trip : $31.11, $25.01, $18.53, $14.37, $24.16, $21.91

Confidence interval = 80%

Average amount spent = 8 to 9 years old

One sample T confidence interval

μ : Mean of variance

80% of confidence interval results :

Using statistical software,

Variable : data

Sample mean : 22.515

Std. Err. = 2.3479945

DF = 5

L. limit : 19.049632

U. Limit : 25.980368

SD = 5.75

Critical value = 1.476

8 0
3 years ago
The distribution of the amount of a certain brand of soda in 16 OZ bottles is approximately normal with a mean of 16.12 OZ and a
elena-14-01-66 [18.8K]

Answer: 90.82%

Step-by-step explanation:

Given : The distribution of the amount of a certain brand of soda in 16 OZ bottles is approximately normal .

Mean : \mu=16.12\text{ OZ}

Standard deviation: \sigma=0.09\text{ OZ}

Let X be the random variable that represents the amount of soda in bottles.

Formula for z-score : z=\dfrac{x-\mu}{\sigma}

Z-score for 16 oz: z=\dfrac{16-16.12}{0.09}=-1.33

Using the standard normal z-distribution table , the probability that the soda bottles that contain more than the 16 OZ is given by :_

P(x>60)=P(z>-1.33)=1-P(x\leq-1.33)=1-0.0917591=0.9082409\approx0.9082\approx90.82\%

Hence, the percentage of the soda bottles that contain more than the 16 OZ advertised is 90.82% .

8 0
3 years ago
A number divided by 7 is –35.
Leviafan [203]

Answer:

-245

Step-by-step explanation:

multiply 7 and -35 to get your answer.

I hope this helped <3

5 0
2 years ago
Read 2 more answers
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