Given that if a ball is dropped from x feet, it bounces up to 2/3 x feet.
And the ball is dropped from 10 feet, that is x=10 feet,
So,before the first bounce it travels 10 feet distance.
Between first and second bounce it travels 
Between second and third bounce, it travels 
Between third and fourth bounce, it travels 
Like that between 29th and 30th bounce, it travels 
Hence total distance traveled is

=![10+20[(\frac{2}{3}) +(\frac{2}{3}) ^{2} +(\frac{2}{3}) ^{3} +.....+(\frac{2}{3} )^{29} ]](https://tex.z-dn.net/?f=10%2B20%5B%28%5Cfrac%7B2%7D%7B3%7D%29%20%2B%28%5Cfrac%7B2%7D%7B3%7D%29%20%5E%7B2%7D%20%2B%28%5Cfrac%7B2%7D%7B3%7D%29%20%5E%7B3%7D%20%2B.....%2B%28%5Cfrac%7B2%7D%7B3%7D%20%29%5E%7B29%7D%20%5D)
= ![10+20[\frac{\frac{2}{3}*(1-(\frac{2}{3})^{29}) }{1-\frac{2}{3} }]](https://tex.z-dn.net/?f=10%2B20%5B%5Cfrac%7B%5Cfrac%7B2%7D%7B3%7D%2A%281-%28%5Cfrac%7B2%7D%7B3%7D%29%5E%7B29%7D%29%20%20%7D%7B1-%5Cfrac%7B2%7D%7B3%7D%20%7D%5D)
= 10+20*2*(1-
)
= 49.9997 feet ≈ 50 feet approximately.
Answer:
yes it can be scaline triangle
we have the inequality

step 1
Find out the first solution (positive case)

The first solution is all real numbers less than or equal to 1.20
Interval (-infinite,1.20]
step 2
Find out the second solution (negative case)

Multiply by -1 both sides

The second solution is all real numbers greater than or equal to -2.8
the interval [-2.8, infinite)
step 3
Find out the solution to the given inequality
The solution is
[-2.8, infinite) ∩ (-infinite,1.20]=[-2.8,1.20]
the solution is the interval [-2.8,1.20]
see the attached figure to better understand the problem
Note that if we add each side of the 2 equations, y will cancel out:
-12x-y+(17x+y)=6+4
5x=10
x=2
Substituting x=2 in either of the equations, we find the value of y.
Let's use the first equation:
-12x-y=6
-24-y=6
-y=24+6
-y=30, so y=-30.
Thus, the solution is (2, -30)
Answer: C
Answer: (x+2)
Step-by-step explanation: