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3 years ago

If john ran 5 kilometer marathon ,how long was that in meters

2 answers:

5 0

<span>5000 meters. The prefix kilo- denotes multiplication of 1000. Using this knowledge, a kilometer can be translated to 1000 meters. The units also each have a shorthanded symbol, kilometer is km and meter is m. 1 km = 1000m Using this, we can rewrite this equation to fit our problem 5 km = ?m Substitute in meters for kilometers. 5 (1000m) = 5000m Giving us the correct answer of 5000 meters.</span>

Dominik [7]3 years ago

4 0

The answer would be 5000 meters.

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Answer:

the answer is a

Step-by-step explanation:

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Find the x coordinates where the line y=3x-18

vovangra [49]

It would be x equals -6.

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The R. R. Bowker Company collects information on the retail prices of books and publishes the data in The Bowker Annual Library

Alina [70]

Answer:

a) $t=\frac{54.97-57.61}{\frac{8.45}{\sqrt{28}}}=-1.653$

The degrees of freedom are given by:

$df=n-1=28-1=27$

$p_v =2*P(t_{(27)}$

b) The conclusion depends on the significance level selected, if the p value is lower than a significance level given we have enough evidence to conclude that the true mean is different from 57.61, otherwise we FAIl to reject the null hypothesis and thare is no evidence to conclude that the true mean is different from 57.61

Step-by-step explanation:

Data provided

$\bar X=54.97$ represent the mean for the retail price

$s=8.45$ represent the sample standard deviation

$n=28$ sample size selected

$\mu_o =57.61$ represent the value that we want to verify

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value for the test

Part a

System of hypothesis

We want to check if the true mean for the reatil price is 57.61 or not, the system of hypothesis would be:

Null hypothesis: $\mu = 57.61$

Alternative hypothesis: $\mu \neq 57.61$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic is given by:

$t=\frac{54.97-57.61}{\frac{8.45}{\sqrt{28}}}=-1.653$

P value

The degrees of freedom are given by:

$df=n-1=28-1=27$

The p value would be:

$p_v =2*P(t_{(27)}$

Part b: Conclusion

The conclusion depends on the significance level selected, if the p value is lower than a significance level given we have enough evidence to conclude that the true mean is different from 57.61, otherwise we FAIl to reject the null hypothesis and thare is no evidence to conclude that the true mean is different from 57.61

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3 years ago

A different class has 254 students, and 58.7% of them are men. How many men are in the class

Vlad [161]

Answer:

432.7 mens ate there in class

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3 years ago

A fair die is tossed 5 times. Let <img src="https://tex.z-dn.net/?f=%5Cdfrac%7Bm%7D%7Bn%7D" id="TexFormula1" title="\dfrac{m}{n}

Ray Of Light [21]

Answer:

m = 1

Step-by-step explanation:

We can suppose that the number we are looking for is for example 5.

(we can do so because the probability is the same for each number - it'sna fair dice)

For the first toss the probability we have 5 is 1/6 (we have 6 numbers on the dice and number 5 is just one of the possible 6 outcomes).

For the second toss the probability we have 5 is again 1/6.

For the rest of 3 tosses we don'tcare what number we will get( we have our two consecutive 5s), so all of the outcomes for the rest of 3 tosses are good for us (probability is 6/6 = 1)

Threfore, the probability to get two consecutive 5s is 1/6 * 1/6 * 1 * 1 * 1 = 1/36.

We can see that m = 1.

4 0

3 years ago