All categories

3 years ago

What is the value of the function at x=−2?

Mathematics

1 answer:

adell [148]3 years ago

5 0

x = -2

function value at x = -2 is intersection of the x value and graph

which is, 3

Hope it is clear:)

You might be interested in

Write 44 as a product of primes using index notation

trasher [3.6K]

Answer:

Step-by-step explanation:

44 = 2 * 2 * 11

= 2² *11

3 0

2 years ago

What is the root?<br> <img src="https://tex.z-dn.net/?f=3-%20%5Csqrt%7Bx%7D%20%3D0%20" id="TexFormula1" title="3- \sqrt{x} =0 "

irga5000 [103]

To solve for x, add 3 to both sides, multiply both sides by -1, then take the square both sides.
$3- \sqrt{x} =0\\- \sqrt{x} =-3 \\ \sqrt{x} =3 \\ x=3^2=9$

4 0

3 years ago

Given the following graph of a system of inequalities, the point (3, 2) _____________.

uysha [10]

That point does not satisfy either inequality.

You can tell it does not satisfy the first portion, due to it being under the shaded line. Secondly, the dotted line goes through it, but that fact that it is dotted makes it not included.

5 0

3 years ago

Can anyone help me evaluate this f(x)=8+4x the functions are 0 and -2.

Fynjy0 [20]

Answer: f(0)=8

f(-2)=0

Step-by-step explanation:

f(0)=8+4(0)

f(0)=8+0

f(0)=8

f(-2)=8+4(-2)

f(-2)=8+(-8)

f(-2)=8-8

f(-2)=0

3 0

1 year ago

Which set of numbers could represent the lengths of the sides of a right triangle?

DiKsa [7]

Answer:

The first set: 8, 15, and 17.

Step-by-step explanation:

By the pythagorean theorem, a triangle is a right triangle if and only if

$\text{longest side}^2 = \text{first shorter side}^2 + \text{second shorter side}^2$ .

In this case,

$\text{longest side}^2 = 17^2 = 289$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 8^2 + 15^2\\ &=64 + 225 = 289 \end{aligned}$ .

In other words, indeed $\text{hypotenuse}^2 = \text{first leg}^2 + \text{second leg}^2$ . Hence, 8, 15, 17 does form a right triangle.

Similarly, check the other pairs. Keep in mind that the square of the longest side should be equal to the sum of the square of the two

Factor out the common factor $2$ to simplify the calculations.

$\text{longest side}^2 = 20^2 = 400$

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 10^2 + 15^2\\ &=100 + 225 = 325 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = (2\times 11)^2 = 2^2 \times 121$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= (2 \times 6)^2 + (2 \times 9)^2\\ &=2^2 \times(36 + 81) = 2^2 \times 117 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = 11^2 = 121$ .

<h3> $\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 7^2 + 9^2\\ &=49+ 81 = 130 \end{aligned}$ .</h3>

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

6 0

3 years ago