Solve the following system by the substitution method.1/4x+2/3y=-17/43x-y=3

1 answer:

6 0

3x - y = 3.....3x - 3 = y

1/4x + 2/3(3x - 3) = -17/4
1/4x + 2x - 2 = -17/4 ...multiply everything by 4
x + 8x - 8 = -17
9x = -17 + 8
9x = - 9
x = -1

3x - y = 3
3(-1) - y = 3
-3 - y = 3
-3 - 3 = y
-6 = y

solution is (-1,-6)

You might be interested in

What happens to the area of a circle when the radius is doubled? (1 point) it is doubled?

Alina [70]

I think the circle would grow bigger into an oval.

7 0

3 years ago

Drawing Conclusions

maksim [4K]

Answer:

Some of the Exponents = -2 that is true, not 2.

Step-by-step explanation:

Let's check one at a time.

(a)The 6 without an exponent is equivalent to the 6 having a 0 exponent.

$6^{0} =1$ and $6^{1}$ = 6 (no exponent. 6 $\neq$ 1 therefore this statement is False.

(b)The sum of the exponents is -2.

let's check , if the base is same we can add the exponents that is the exponent rule.(well established).

if we add exponents in the given expression we get.

$6^{1} 6^{0} 6^{3} =6^{1+0+(-3)} =6^{-2}$ , therefore we can see that the sum of the exponents = -2 this is true.

(c) An equivalent expression is 65.6-7, lets evaluate our above expression, it is equal to $\frac{1}{36}$ which we can see that $\frac{1}{36} \neq 65.6-7$ ,therefore this statement is false as well.