Origin is the corner of square whose one side is 3 X + 4 Y + 5 = 0 find its area.
1 answer:
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Answer:
- modulus: 3√2
- argument: -3π/4 (or 5π/4)
Step-by-step explanation:
The modulus is the magnitude of the complex number; the argument is its angle (usually in radians).
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<h3>rectangular form</h3>The complex number can be cleared from the denominator by multiplying numerator and denominator by its conjugate:
The magnitude of this number is the root of the sum of the squares of the real and imaginary parts:
modulus = √((-3)² +(-3)²) = 3√2
The argument is the arctangent of the ratio of the imaginary part to the real part, taking quadrant into consideration.
arg = arctan(-3/-3) = -3π/4 or 5π/4 . . . . radians
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modulus∠argument = (3√2)∠(-3π/4)
Answer:
The image coordinates are D'(8, 5), E'(12, 3) and F'(10,0)
Step-by-step explanation:
Given the vertices of △ DEF are D (2, 5), E (6, 3), and F (4, 0). We have to translate the triangle using the vector (6, 0)
Now, translation by vector (6, 0)
D (2, 5)=D'(2+6, 5+0)=D'(8, 5)
E (6, 3)=E'(6+6, 3+0)=E'(12, 3)
F (4, 0)=F'(4+6, 0+0)=F'(10,0)
Now, we have to label the coordinate of the triangle or to get image of triangle after translation.
Hence, The image coordinates are D'(8, 5), E'(12, 3) and F'(10,0)
