Question

Origin is the corner of square whose one side is 3 X + 4 Y + 5 = 0 find its area.

Answer 1

Answer:

The correct option is;

a. 1

Step-by-step explanation:

Given that the origin (0, 0) is the corner of the square

The equation of one of the sides = 3·X + 4·Y + 5 = 0

Therefore, we have;

Y = -3/4·X - 5/4

Which gives the slope as -3/4 and the y-intercept as (0, -5/4)

The sloe of the perpendicular side from the origin to the given line is therefore = -(1/(3/4)) = 4/3

The y-intercept of the current particular perpendicular side = 0

The equation is therefore;

y = 4/3·x + 0

The coordinate of the point of intersection of the two sides of the square above is found by equating the two lines to each other as follows;

4/3·x = -3/4·X - 5/4

4/3·x + 3/4·X = -5/4

25/12·X = -5/4

X = -5/4×12/25 = -3/5

Y = 4/3·x = 4/3× (-3/5) =-4/5

The length of a side = √((-3, 5) - 0)² + ((-4, 5) - 0)² = √1 = 1

The area of a square = (Length of side) × (Length of side)

∴ The area of the square = 1 × 1 = 1

The area of the square  = 1.