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3 years ago

Origin is the corner of square whose one side is 3 X + 4 Y + 5 = 0 find its area.

Mathematics

1 answer:

cricket20 [7]3 years ago

6 0

Answer:

The correct option is;

a. 1

Step-by-step explanation:

Given that the origin (0, 0) is the corner of the square

The equation of one of the sides = 3·X + 4·Y + 5 = 0

Therefore, we have;

Y = -3/4·X - 5/4

Which gives the slope as -3/4 and the y-intercept as (0, -5/4)

The sloe of the perpendicular side from the origin to the given line is therefore = -(1/(3/4)) = 4/3

The y-intercept of the current particular perpendicular side = 0

The equation is therefore;

y = 4/3·x + 0

The coordinate of the point of intersection of the two sides of the square above is found by equating the two lines to each other as follows;

4/3·x = -3/4·X - 5/4

4/3·x + 3/4·X = -5/4

25/12·X = -5/4

X = -5/4×12/25 = -3/5

Y = 4/3·x = 4/3× (-3/5) =-4/5

The length of a side = √((-3, 5) - 0)² + ((-4, 5) - 0)² = √1 = 1

The area of a square = (Length of side) × (Length of side)

∴ The area of the square = 1 × 1 = 1

The area of the square = 1.

You might be interested in

what is the equation in point-slope form of the line passing through (0, 5) and (−2, 11)? (1 point) y − 5

makkiz [27]

According to the question, the line is through the points $(0,5)$ and $(-2,11)$

To calculate the slope using standard formula that is :

$m = \frac{(y(2)-y(1))}{(x(2)-x(1))} = \frac{(11-5)}{(-2-0)} =\frac{6}{-2} = -3$

Now the slope equation will be: $m(x(2)-x(1)) = (y(2)-y(1))$

$y-5 =(-3)(x-0) = y = -3(x)+5$

The slope-intercept form is: $y = -3x+5$

What is the equation of the line?

To represent the set of points in an algebraic form is known as the equation of line. The set of points represent lines in the coordinate system. The parameters can be calculated and those parameters are slope and y-intercept.

To learn more about the equation of the line from the given link:

<u>brainly.com/question/14037984</u>

#SPJ4

5 0

1 year ago

TOY has coordinates T (-3, 4), O (-4, 1) and Y (-2, 3). a translation maps point T to T' (-1, 1). find the coordinates of O' and

NeX [460]

Answer:

Answer: The correct option is (A) O' (−2, −2); Y' (0, 0).

Step-by-step explanation: Given that the co-ordinates of the vertices of ΔTOY are T(−3, 4), O (−4, 1), and Y (−2, 3). A translation maps point T to T' (−1, 1).

We are to find the co-ordinates of the points O' and Y'.

The given transformation from T to T' is

T(−3, 4) ⇒ T' (−1, 1).

Let, (−3 + x, 4 + y) = (-1, 1).

So,

and

That is, the transformation rule is

(a, b) ⇒ (a+2, b-3).

Therefore,

co-ordinates of O' are (-4+2, 1-3) = (-2, -2),

and

co-ordinates of Y' are (-2+2, 3-3) = (0, 0).

Thus, the required co-ordinates of O' and Y' are (-2, -2) and (0, 0) respectively.

Option (A) is correct.

8 0

3 years ago

You are given the following sequence:

borishaifa [10]

<h2> Question No 1</h2>

Answer:

7.5 is the 4th term of the sequence $60, 30, 15, 7.5, ...$ .

In other words: $\boxed{a_4=7.5}$

Step-by-step explanation:

Considering the sequence

$60, 30, 15, 7.5, ...$

As we know that a sequence is said to be a list of numbers or objects in a special order.

$60, 30, 15, 7.5, ...$

is a sequence starting at 60 and decreasing by half each time. Here, 60 is the first term, 30 is the second term, 15 is the 3rd term and 7.5 is the fourth term.

In other words,

$a_1=60$ ,

$\:a_2=30$ ,

$a_3=15$ , and

$a_4=7.5$

Therefore, 7.5 is the 4th term of the sequence $60, 30, 15, 7.5, ...$ .

In other words: $\boxed{a_4=7.5}$

<h2> Question # 2</h2>

Answer:

The value of a subscript 5 is 16.

i.e. When n = 5, then h(5) = 16

Step-by-step explanation:

To determine:

What is the value of a subscript 5?

Information fetching and Solution Steps:

Chart with two rows.

The first row is labeled n.

The second row is labeled h of n. i.e. h(n)

The first row contains the numbers three, four, five, and six.

The second row contains the numbers four, nine, sixteen, and twenty-five.

Making the data chart

n 3 4 5 6

h(n) 4 9 16 25

As we can reference a specific term in the sequence by using the subscript. From the table, it is clear that 'n' row represents the input and and 'h(n)' represents the output.

So, when n = 5, the value of subscript 5 corresponds with 16. In other words: When n = 5, then h(5) = 16

Therefore, the value of a subscript 5 is 16.

<h2> Question # 3</h2>

Answer:

We determine that the sequence 33, 31, 28, 24, 19, … is neither arithmetic nor geometric.

Step-by-step explanation:

Considering the sequence

33, 31, 28, 24, 19, …

Lets calculate the common difference 'd' to determine if the sequence is Arithmetic or not.

$\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n$

$d = 31 - 33 = -2$

$d = 28 - 31 = -3$

$d = 24 - 28 = -4$

$d = 19 - 24 = -5$

As the common difference 'd' is not constant. It means the sequence is not Arithmetic.

Lets now calculate the common ratio 'r' to determine if the sequence is Geometric or not.

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_n}{a_{n-1}}$

$\frac{31}{33}=0.93939\dots ,\:\quad \frac{28}{31}=0.90322\dots ,\:\quad \frac{24}{28}=0.85714\dots ,\:\quad \frac{19}{24}=0.79166\dots$

The ratio is not constant. It means the sequence is not Geometric.

From the above analysis, we determine that the sequence 33, 31, 28, 24, 19, … is neither arithmetic nor geometric.

<h2> Question # 4</h2>

Answer:

We determine that the sequence -99, -96, -92, -87, -81... is neither arithmetic nor geometric.

Step-by-step explanation:

From the description statement:

''negative 99 comma negative 96 comma negative 92 comma negative 87 comma negative 81 comma dot dot dot''.

The statement can be translated algebraically as

-99, -96, -92, -87, -81...

Lets calculate the common difference 'd' to determine if the sequence is Arithmetic or not.

$\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n$

$-96-\left(-99\right)=3,\:\quad \:-92-\left(-96\right)=4,\:\quad \:-87-\left(-92\right)=5,\:\quad \:-81-\left(-87\right)=6$

As the common difference 'd' is not constant. It means the sequence is not Arithmetic.

Lets now calculate the common ratio 'r' to determine if the sequence is Geometric or not.

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_n}{a_{n-1}}$

$\frac{-96}{-99}=0.96969\dots ,\:\quad \frac{-92}{-96}=0.95833\dots ,\:\quad \frac{-87}{-92}=0.94565\dots ,\:\quad \frac{-81}{-87}=0.93103\dots$

The ratio is not constant. It means the sequence is not Geometric.

From the above analysis, we determine that the sequence -99, -96, -92, -87, -81... is neither arithmetic nor geometric.

<h2> Question # 5</h2>

Step-by-step explanation:

Considering the sequence

12, 22, 30, 36, 41, …

$\mathrm{Compute\:the\:differences\:of\:all\:the\:adjacent\:terms}:\quad \:d=a_{n+1}-a_n$

$22-12=10,\:\quad \:30-22=8,\:\quad \:36-30=6,\:\quad \:41-36=5$

As the common difference 'd' is not constant. It means the sequence is not Arithmetic.

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_n}{a_{n-1}}$

$\frac{22}{12}=1.83333\dots ,\:\quad \frac{30}{22}=1.36363\dots ,\:\quad \frac{36}{30}=1.2,\:\quad \frac{41}{36}=1.13888\dots$

The ratio is not constant. It means the sequence is not Geometric.

From the above analysis, we determine that the sequence 12, 22, 30, 36, 41, … is neither arithmetic nor geometric.

8 0

3 years ago

I need help :)<br> Find the GCF: 10x^5−16x^4+4x^2

andreev551 [17]

The greatest common factor is 2x^2.
the largest number that divides evenly into <span>10x^5−16x^4+4x^2 is two.
the highest degree is x^2 so the answer would be 2x^2
</span>

5 0

3 years ago

When you multiply a number by 1/4

miss Akunina [59]

Answer:

The answer is D

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers