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3 years ago

What is the mean, median and mode of the following data?

Mathematics

2 answers:

rewona [7]3 years ago

4 0

Answer:

mean = 14.8, median = 13, mode = 12

Step-by-step explanation:

Mean: sum the values then divide by the total number of values

Median: the middle value once the values are placed in order from smallest to greatest. if the number of values is even, then take the average of the middle 2 values.

Mode: the value that occurs most often

Mean: (14 + 22 + 18 + 12 + 14 + 8 + 4 + 12 + 32 + 12) ÷ 10 = 14.8

Place the numbers in order:

4, 8, 12, 12, 12, 14, 14, 18, 22, 32

Median: (12 + 14) ÷ 2 = 13

Mode: 12

balu736 [363]3 years ago

3 0

Answer:

Step-by-step explanation:

I just did what your supposed to do.

Hope this helps have agreat afternoon:)

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3 years ago

There are 14 juniors and 16 seniors in a chess club. a) From the 30 members, how many ways are there to arrange 5 members of the

Dmitrij [34]

Answer:

a) 17,100,720

b) 4,717,440

c) 10,920

d) 2821

Step-by-step explanation:

14 juniors and 16 seniors = 30 people

a) From the 30 members, how many ways are there to arrange 5 members of the club in a line?

As it is a ordered arrangement

30.29.28.27.26 = 17,100,720

b) How many ways are there to arrange 5 members of the club in a line if there must be a senior at the beginning of the line and at the end of the line?

16.28.27.26.15 = 4,717,440

c) If the club sends 2 juniors and 2 seniors to the tournament, how many possible groupings are there?

Not ordered arrangement. And means that we need to multiply the results.

C₁₄,₂ * C₁₆,₂

C₁₄,₂ = 14.13.12! = 14.13 = 91

12! 2! 2

C₁₆,₂ = 16.15.14! = 16.15 = 120

14! 2! 2

C₁₄,₂ * C₁₆,₂ = 91.120 = 10,920

d) If the club sends either 4 juniors or 4 seniors, how many possible groupings are there?

Or means that we need to sum the results.

C₁₄,₄ + C₁₆,₄

C₁₄,₄ = 14.13.12.11.10! = 14.13.12.11 = 1001

10! 4! 4.3.2.1

C₁₆,₄ = 16.15.14.13.12! = 16.15.14.13 = 1820

12! 4! 4.3.2.1

C₁₄,₄ + C₁₆,₄ = 1001 + 1820 = 2821

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