For each sequence find the first 4 terms and the 10th term
1 answer:
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For this case, the dividend is given by:
We note that the following numbers:
2, 10, 1, 5
They are the coefficients of the polynomial and they are in the upper part of the division.
The number -5 is the opposite value of the divisor constant.
Therefore, the divisor is given by:
x + 5
Answer:
The divisor is:
x + 5
We note that the following numbers:
2, 10, 1, 5
They are the coefficients of the polynomial and they are in the upper part of the division.
The number -5 is the opposite value of the divisor constant.
Therefore, the divisor is given by:
x + 5
Answer:
The divisor is:
x + 5
Question: Given that BE bisects ∠CEA, which statements must be true? Select THREE options.
(See attachment below for the figure)
m∠CEA = 90°
m∠CEF = m∠CEA + m∠BEF
m∠CEB = 2(m∠CEA)
∠CEF is a straight angle.
∠AEF is a right angle.
Answer:
m∠CEA = 90°
∠CEF is a straight angle.
∠AEF is a right angle
Step-by-step explanation:
Line AE is perpendicular to line CF, which is a straight line. This creates two right angles, <CEA and <AEF.
Angle on a straight line = 180°. Therefore, m<CEA + m<AEF = m<CEF. Each right angle measures 90°.
Thus, the three statements that must be TRUE are:
m∠CEA = 90°
∠CEF is a straight angle.
∠AEF is a right angle
