Answer:
1430
Step-by-step explanation:
Given that a standard deck of cards is 52 cards, we have 13 Diamonds and we need 4 diamonds.
Hence, we have 13C4.
Also, we have 4 kings in a standard deck of cards, and in which we have 2 black kings but we need 1 king.
Hence we have a 2C1
Therefore:
13C4 * 2C1
=> 13! ÷ [4! (13 - 4)!] * 2! ÷ [1! (2-1)!]
=> 13! ÷ [4! (9)!]
=> (1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 10 x 11 x 12 x 13) ÷ [(1 x 2 x 3 x 4) (1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9)]
=> (10 x 11 x 12 x 13) ÷ 24
=> (17160 ÷ 24) * (24 ÷ 6)
=> 715
2! ÷ [1! (2-1)!]
=> 2
Hence, we have 715 * 2
=> 1430
Hence, in this case, the correct answer to the question is 1430
143 cards, you can find this using the LCM or least common multiple. <span />
4 cos² x - 3 = 0
4 cos² x = 3
cos² x = 3/4
cos x = ±(√3)/2
Fixing the squared cosine doesn't discriminate among quadrants. There's one in every quadrant
cos x = ± cos(π/6)
Let's do plus first. In general, cos x = cos a has solutions x = ±a + 2πk integer k
cos x = cos(π/6)
x = ±π/6 + 2πk
Minus next.
cos x = -cos(π/6)
cos x = cos(π - π/6)
cos x = cos(5π/6)
x = ±5π/6 + 2πk
We'll write all our solutions as
x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k
