Answer:
A. segment PS ≅ segment QR
Step-by-step explanation:
Given that the quadrilateral PQRS is a rectangle then;
- The diagonals are PR and SQ
- Point of intersection of diagonals is T
- Segment PS≅ Segment QR
- ∠PSQ≅ ∠SQR
- segment SR≅ segment PQ
I think 42
would be the best answer to your question in my opininon.
Answer:
Step-by-step explanation:
Consider the given expression is
![\ln (x\sqrt[3]{x^2+1})](https://tex.z-dn.net/?f=%5Cln%20%28x%5Csqrt%5B3%5D%7Bx%5E2%2B1%7D%29)
We need to rewrite the expression as a sum,difference,or multiple of logarithms.
![[\because \sqrt[n]{x}=x^{\frac{1}{n}}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%5Bn%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%5D)
Using the properties of logarithm we get
![[\because \ln (ab)=\ln a+\ln b]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20%28ab%29%3D%5Cln%20a%2B%5Cln%20b%5D)
![[\because \ln (a^b)=b\ln a]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20%28a%5Eb%29%3Db%5Cln%20a%5D)
Therefore, the simplified form of the given expression is
.
V=(1/3)hpir^2
v=130
h=13
r=x
130=(1/3)(13)pix^2
times both sides by 3
390=13pix^2
divide both sides by 13
30=pix^2
divide both sides by pi
30/pi=x^2
sqrt both sides
x≈3.09
radius is abou 3 units