Answer:
<em> 1,407</em>
<em>x 14</em>
<em>_______</em>
<em> 5,628</em>
<em>+ 1,4070</em>
<em>______</em>
19,698
<em>The two partial products are 5,628 and 14,070</em>
Common factors of 50: 1, 2, 5, 10, 25, 50
Common factors of 30: 1, 2, 3, 5, 6, 10, 15, 30
Common factors of 100: 1, 2, 4, 5, 10, 20, 25, 50, 100
You're welcome.
Answer:
1,2,3,5
Step-by-step explanation:
1-Is your job as an IT administrator stressful?
2-What is your biggest source of stress?
3-How has your job impacted your personal life?
5-Have you ever considered switching careers because of on-the-job stress?
Answer:
16,17,18,18,19,19,21,21,21,22,22,22,24,25,28,29,30
Answer:
There are 15 letters, but if the two A's must always be together, that's the same as if they're just one letter, so our "base count" is 14! ; note that this way of counting means that we also don't need to worry about compensating for "double counting" identical permutations due to transposition of those A's, because we don't "count" both transpositions. However, that counting does "double count" equivalent permutations due to having two O's, two N's, and two T's, so we do need to compensate for that. Therefore the final answer is 14!/(23)=10,897,286,400
