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ratelena [41]
3 years ago
9

Katherine is working two summer jobs, making $16 per hour lifeguarding and making $6 per hour walking dogs. In a given week, she

can work a maximum of 15 total hours and must earn at least $160.
Mathematics
1 answer:
Mama L [17]3 years ago
3 0

Answer:

7 hours working as a lifeguard and 8 hours walking dogs

Step-by-step explanation:

16×7=122 and 6×8=48

122+48=160

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What are the rules which say what to calculate first, PEMDAS.
n200080 [17]

Confused on this question

3 0
3 years ago
Read 2 more answers
Desiree writes songs for her band her first song is 3 1/2 minutes long her second song is one 1/2 times as long as her first son
vesna_86 [32]

Answer:Number of minutes of second  Song = 5 1/4 minutes

Number of minutes of third   Song =3 1/2  minutes

Step-by-step explanation:

Number of minutes of First Song = 3 1/2 minutes

Number of minutes of second  Song = one 1/2 times as long as her first

= 1 1/2 X 3 1/2 minutes

3/2 X 7/2

21/4 = 5 1/4 minutes

Number of minutes of third   Song = 2/3 times as long as her second song

2/ 3 x 5 1/4

= 2/3 x 21/4 =42/12

Dividing the numerator and denominator by 3 to reduce the fraction

42/ 12 / 3/3 = 14/4

14/4 = 3 2/4 = 3 1/2  minutes

5 0
3 years ago
In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x
Alexus [3.1K]

Answer:

Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

Step-by-step explanation:

Given Differential Equation,

y"-2y'+y=xe^x ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

\implies\:y(x)=y_c(x)+y_p(x)

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

y_c(x)=C_1e^x+c_2xe^x

Now for particular solution,

let y_p(x)=Ax^3e^x

y'=Ax^3e^x+3Ax^2e^x

y"=Ax^3e^x+6Ax^2e^x+6Axe^x

Now putting these values in (1), we get

Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x

Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x

6Axe^x=xe^x

6A=1

A=\frac{1}{6}

\implies\:y_p(x)=\frac{x^3e^x}{6}

Therefore, Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

8 0
4 years ago
What is 2 (m+6)= 48?
aleksklad [387]
M= 18

Have a good day
4 0
3 years ago
Read 2 more answers
Help fast pleaseeeeeeee
anyanavicka [17]

Step-by-step explanation:

  • -2. = \frac{1}{49}
  • -1 = \frac{1}{7}
  • 0 = 1
  • 1. = 7
  • 2. = 49
8 0
3 years ago
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