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lidiya [134]
3 years ago
14

PLEASE HELP!!! Write the equation of a line that goes through the point (6, 3) and is perpendicular to the line y = 4x + 1.

Mathematics
1 answer:
Tpy6a [65]3 years ago
8 0

For this case we have that by definition, the equation of a line in the point-slope form is given by:

y-y_ {0} = m (x-x_ {0})

Where:

m: It is the slope of the line and (x_ {0}, y_ {0})is a point through which the line passes.

We have the following equation of the slope-intersection form:

y = 4x + 1

Where the slope is m = 4

By definition, if two lines are perpendicular then the product of their slopes is -1.

Thus, a perpendicular line will have a slope:

m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {4}\\m_ {2} = - \frac {1} {4}

Thus, the equation will be of the form:

y-y_ {0} = - \frac {1} {4} (x-x_ {0})

Finally we substitute the given point and we have:

y-3 = - \frac {1} {4} (x-6)

Answer:

Option B

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