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Sergio [31]
3 years ago
10

Yo can someone please help me.

Mathematics
1 answer:
Novay_Z [31]3 years ago
3 0

Answer:

44670

Step-by-step explanation:

5.67*1000+3.9*10000

You might be interested in
6. All angles in the figure below are right angles. What is the area of the figure? (1 point)
lilavasa [31]

Answer:

Option (4)

Step-by-step explanation:

Area of the figure given in the picture = Area of large rectangle - Area of rectangle A

Area of rectangle A = Length × Width

                                 = [9 - (2 + 4)] × 3

                                 = 3 × 3

                                 = 9

Area of the large rectangle = Length × Width

                                             = 9 × 5

                                             = 45

Therefore, area of the given figure = 45 - 9

                                                          = 36

Option (4) will be the correct option.

5 0
3 years ago
The ratios in an equivalent ratio table are 3:12, 4:16, and 5:20. If the first number in the ratio is 10, what is the second num
krek1111 [17]

Answer:

10:40

Step-by-step explanation:

7 0
3 years ago
Jesse wants to build a wooden chest with a volume of 8,100 cubic inches .The length will be 30 inches and the width will be 15 i
Andrew [12]
Depth = 18 cubic inches
3 0
3 years ago
Read 2 more answers
What is the circumference of the circle if r = 3.5 feet? Use 22 7 for π.45 pts
Natasha_Volkova [10]
We know, Circumference of a Circle = 2πr
C = 2 * 22/7 * 3.5
C = 2 * 22/2
C = 2 * 11
C= 22

In short, Your Answer would be 22 Feet 

Hope this helps!
6 0
3 years ago
Read 2 more answers
Find the first three iterates of the function f(z) = z2 + c with a value of c = 2 - 3i and an initial value of z0 = 1 + 2i.
Artist 52 [7]

Answer:

C

Step-by-step explanation:

We have: (I rewrote the function)

f(z_n)={z_{n-1}} ^2+c

Given that:

\displaystyle c=2-3i \text{ and } z_0 = 1 + 2 i

The first iterate will be:

\displaystyle \begin{aligned} f(z_1)&=(z_0)^2+c \\ &=(1+2i)^2+(2-3i) \\ &= (1+4i+4i^2)+(2-3i) \\ &=1+4i-4+2-3i \\ &=-1+i \end{aligned}

The second iterate will be:

\begin{aligned}f(z_2) &=(z_1)^2+c\\ &=(-1+i)^2+(2-3i) \\&= (1-2i+i^2)+(2-3i) \\&=1-2i-1+2-3i \\&=2-5i \end{aligned}

And the third iterate will be:

\begin{aligned} f(z_3)&=(z_2)^2+c\\ &=(2-5i)^2+(2-3i) \\ &=(4-20i+25i^2)+(2-3i) \\ &=4-20i-25+2-3i \\ &=-19-23i \end{aligned}

Hence, our answer is C.

3 0
3 years ago
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