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3 years ago

The original price of the shirt was $79.99. It is on sale for $49.99. What is the percent discount? Round to the nearest tenth.

Mathematics

2 answers:

vitfil [10]3 years ago

5 0

The answer is 37.5% off

Temka [501]3 years ago

5 0

You basically just saved $30 so I say nearly 24%

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Fill in the blanks to complete the area model to solve 6.60 divided by 15 is the same as _ x ? = _ 6.60 = _ hundredths

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Answer:

$15 x = 6.60$

$x = 44\ hundredths$

Step-by-step explanation:

Given

$\frac{6.60}{15}$

Required

Complete the model

[ ] x = 6.60

x = _ hundredths

$\frac{6.60}{15}$

Equate to x

$x = \frac{6.60}{15}$

Multiply both sides by 15

$15 * x = \frac{6.60}{15} * 15$

$15 * x = 6.60$

$15 x = 6.60$

So, we have:

[ ] x = 6.60 =====> $15 x = 6.60$

Recall that:

$x = \frac{6.60}{15}$

$x = 0.44$

This implies that:

$x = 44\ hundredths$

Hence:

x = _ hundredths =====> $x = 44\ hundredths$

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A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

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