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IrinaK [193]
3 years ago
9

joes family has compleated 60% of a road trip. if they have traveld 30 miles, how far is the full road trip?

Mathematics
1 answer:
Tems11 [23]3 years ago
4 0

The full road trip is 50 miles.

Step-by-step explanation:

Given,

Distance traveled by Joe's family = 30 miles

This represents 60% of the total distance to be traveled.

Let,

x be the total distance.

60% of x = 30

\frac{60}{100}*x=30\\0.6x=30

Dividing both sides by 0.6

\frac{0.6x}{0.6}=\frac{30}{0.6}\\x=50\ miles

The full road trip is 50 miles.

Keywords: percentage, division

Learn more about percentages at:

  • brainly.com/question/3375830
  • brainly.com/question/3398261

#LearnwithBrainly

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Captain Sparrow and his pirate crew dug up several gold coins. They are dividing the coins amongst themselves so that each perso
Dahasolnce [82]

Answer: 150 coins

Step-by-step explanation: let the number of captain Sparrow and the crew = c

The number of gold = g

This mean each person will get g/c

If there were four fewer pirates, then each person would get 10 more coins means

g/(c - 4) = g/ c+ 10

cg = (c-4)(g+10c) ....... (1)

However, if there were 50 fewer coins, then each person would get 5 fewer coins.

(g - 50)/c = g/c - 5

g - 50 = g - 5c

5c = 50

c = 10

Substitute c in equation 1

cg = (c-4)(g+10c) ....... (1)

10g = (10 - 4)(g + 10×10)

10g = 6× (g + 100)

10g = 6g + 600

4g = 600

g = 150 gold coin.

Therefore they dig up 150 gold coin

5 0
3 years ago
This Spring, Daisy wanted to
meriva
5•6 = 30.

She needs to buy 30 flowers from the store.
8 0
3 years ago
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I need the answer fast pls
Naddik [55]

Answer:

A: The interquartile range is 8.

Step-by-step explanation:

Hopefully this helps!

8 0
3 years ago
An article includes the accompanying data on compression strength (lb) for a sample of 12-oz aluminum cans filled with strawberr
Sliva [168]

Answer:

A) Option B is correct.

H₀: μ₁ = μ₂

Hₐ: μ₁ - μ₂ < 0

B) t = -2.502

p-value = 0.0112

C) Option A is correct.

Reject H₀. The data suggests that cola has a higher average compression strength than the strawberry drink.

D) Option A is correct.

The distributions of compression strengths are approximately normal.

Step-by-step explanation:

The complete Question is presented in the two attached images to this answer.

A) To perform this test we first define the null and alternative hypothesis.

The null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test.

While, the alternative hypothesis usually confirms the the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test.

For this question, we want to test if the extra carbonation of cola results in a higher average compression strength. That is, that cola has a higher average compression strength than the strawberry drink.

Hence, the null hypothesis would be that there isn't significant evidence to suggest that the extra carbonation of cola results in a higher average compression strength, that is, cola has a higher average compression strength than the strawberry drink.

The alternative hypothesis is that there is significant evidence to suggest that the extra carbonation of cola results in a higher average compression strength, that is, cola has a higher average compression strength than the strawberry drink.

Mathematically, if the average compression strength of strawberry drink is μ₁, the average compression strength of cola is μ₂ and the difference in compression strengths is μ = μ₁ - μ₂

The null hypothesis is represented as

H₀: μ = 0 or μ₁ = μ₂

The alternative hypothesis is represented as

Hₐ: μ < 0 or μ₁ - μ₂ < 0

B) So, to perform this test, we need to compute the test statistic

Test statistic for 2 sample mean data is given as

Test statistic = (μ₁ - μ₂))/σ

σ = √[(s₂²/n₂) + (s₁²/n₁)]

μ₁ = average compression strength of strawberry drink = 537

n₁ = sample size of the sample of strawberry drink in cans surveyed = 10

s₁ = standard deviation of the compression strength of strawberry drink in cans surveyed= 22

μ₂ = average compression strength of cola = 559

n₂ = sample size of the sample of cola in cans surveyed = 10

s₂ = standard deviation of the compression strength of strawberry drink in cans surveyed = 17

σ = [(17²/10) + (22²/10)] = 77.5903160379 = 8.792

We will use the t-distribution as no information on population standard deviation is provided

t = (537 - 559) ÷ 8.792

= -2.502 = -2.50

checking the tables for the p-value of this t-statistic

Degree of freedom = df = n₁ + n₂ - 2 = 10 + 10- 2 = 18

Significance level = 0.05

The hypothesis test uses a one-tailed condition because we're testing in only one direction (whether compression strength of cola in can is greater).

p-value (for t = -2.50, at 0.05 significance level, df = 18, with a one tailed condition) = 0.011154 = 0.0112 to 4 d.p.

C) The interpretation of p-values is that

When the (p-value > significance level), we fail to reject the null hypothesis and when the (p-value < significance level), we reject the null hypothesis and accept the alternative hypothesis.

So, for this question, significance level = 0.05

p-value = 0.0112

0.0112 < 0.05

Hence,

p-value < significance level

This means that we reject the null hypothesis accept the alternative hypothesis & say that the extra carbonation of cola results in a higher average compression strength, that is, cola has a higher average compression strength than the strawberry drink.

D) The necessary conditions required before a t-test is deemed valid include.

- The samples used must be a random sample of the population distribution with each variable in the sample independent of other one.

- The distribution of the population where the samples were extracted from must be normal or approximately normal to ensure some degree of normality for the samples.

Hence, the necessary assumption for this t-test among the options is that the distributions of compression strengths are approximately normal.

Hope this Helps!!!

7 0
3 years ago
A ball is shot into the air using a brand new super-high-tech robotic arm to help baseball players practice catch fly balls.
stepladder [879]

Answer:

69 feet

Step-by-step explanation:

we have

h(t)=-16t^{2}+64t+5

where

h(t) is the height of the ball

t is the time in seconds

we know that the given equation is a vertical parabola open downward

The vertex is the maximum

so

the y-coordinate of the vertex represent the maximum height of the ball

Convert the quadratic equation into vertex form

The equation in vertex form is equal to

y=(x-h)^{2}+k

where

(h,k) is the vertex of the parabola

h(t)=-16t^{2}+64t+5

h(t)-5=-16t^{2}+64t

h(t)-5=-16(t^{2}-4t)

h(t)-5-64=-16(t^{2}-4t+4)

h(t)-69=-16(t^{2}-4t+4)

h(t)-69=-16(t-2)^{2}

h(t)=-16(t-2)^{2}+69

the vertex is the point (2,69)

therefore

The maximum height is 69 ft

6 0
3 years ago
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