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slega [8]
3 years ago
12

Let the Universal Set, S, have 140 elements. A and B are subsets of S. Set A contains 76 elements and Set B contains 16 elements

. If the total number of elements in either A or B is 91, how many elements are in A but not in B?
Mathematics
1 answer:
Vlada [557]3 years ago
7 0

Answer:

the number of elements are in A but not in B

n(A-B) = 75

Step-by-step explanation:

Given  universal set (S) = 140

also given A and B are subsets of 'S'

Given n(A) = 76 , n(B) =16 and n(AUB) =91

we have to find n(A-B) ?

we can use formula

n(A-B) = n(AUB)-n(B)

          = 91 - 16 =75

<u>Final answer</u>:-

the number of elements are in A but not in B

n(A-B) = 75

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