1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Maksim231197 [3]
3 years ago
7

1. In a mechanical design, it is recommended to use standard size/dimension to overcome uncertainties in stress or material stre

ngth.
A. True
B. False
2. Steels' surface fatigue strength can be correlated to their Brinell hardnesses.
A. True
B. False
3. If a material point has three principal stresses 01 = 02 = 03 = 300kpsi, then the maximum shear stress is Tmax = 150kpsi.
A. True
B. False
4. The endurance limit of a material is independent on the size of a part.
A. True
B. False
5. The tensile stress in a bolt is usually calculated through tensile force divided by area of unthreaded rod's cross-section area.
A. True
B. False
6. Edge shear-out or tear-out is one failure mode in bolted or riveted joints.
A. True
B. False
7. Pretension of bolts can be controlled by a torque wrench.
A. True
B. False
8. The material ultimate tensile strength of a spring coil is dependent on its coil diameter.
A. True
B. False
9. Adhesive joints are much stronger in tensile loading than shear loading.
A. True
B. False
10. The dominated loading condition in a helical spring is torsion along coils.
A. True
B. False
11. The principal advantage of conical springs is that the its spring rate is non-linear.
A. True
B. False
12. The dimensions of a bearing is coded by two-digit series numbers according to ABMA, one digit for width and the other one for diameter.
A. True
B. False
13. Three key things to determine selection of bearing are load, life and reliability.
A. True
B. False
14. Straight roller bearings can carry large radial loads and small amount of axial load.
A. True
B. False
15. In the AGMA method of gear analysis, gear strength values are the true material strengths.
A. True
B. False
16. A planetary gear train allows for two degrees of freedom.
A. True
B. False
Engineering
1 answer:
Alex787 [66]3 years ago
6 0

Answer:

1. A.True

2. B.False

3. B.False

4. A.True

5. A.True

6. A.True

7. A.True

8. B.False

9. B.False

10. A.True

11. B.False

12. A.True

13. A.True

14. B.False

15. B.False

16. A.True

Explanation:

Most steels have endurance and fatigue limit about half the Tensile strength. Tensile strength of material is the limit of stress at which material then breaks. The tensile stress in a bolt is calculated through tensile force.

You might be interested in
What is electrical energy used for?
FromTheMoon [43]

Answer:

to power devices  appliances and  some methods of transportation

Explanation:

6 0
3 years ago
Read 2 more answers
As cylinder pressure and heat increase due to an increased load condition, the fuel injection management system must ___________
Temka [501]

possible Answers:

Compensate ⭐⭐⭐⭐⭐

Adjust            ⭐⭐⭐⭐⭐

regulate         ⭐⭐⭐⭐

tune               ⭐⭐⭐

calibrate        ⭐⭐⭐

balance         ⭐⭐

correct           ⭐

6 0
2 years ago
When you multiply monomials with the same variables, you multiply the coefficients and add the exponents!
RideAnS [48]

Answer: ok

Explanation:

this isn't a question?

3 0
3 years ago
Which is a reason that teen might choose to focus on a friendship and not a romantic relationship
andrey2020 [161]

Answer: b. To avoid having distractions

Trust me it’s definitely option b

4 0
4 years ago
Read 2 more answers
An aircraft component is fabricated from an aluminum alloy that has a plane strain fracture toughness of 40MPa. It has been dete
Nataly [62]

Answer:

Yes, fracture will occur

Explanation:

Half length of internal crack will be 4mm/2=2mm=0.002m

To find the dimensionless parameter, we use critical stress crack propagation equation

\sigma_c=\frac {K}{Y \sqrt {a\pi}} and making Y the subject

Y=\frac {K}{\sigma_c \sqrt {a\pi}}

Where Y is the dimensionless parameter, a is half length of crack, K is plane strain fracture toughness, \sigma_c  is critical stress required for initiating crack propagation. Substituting the figures given in question we obtain

Y=\frac {K}{\sigma_c \sqrt {a\pi}}= \frac {40}{300\sqrt {(0.002*\pi)}}=1.682

When the maximum internal crack length is 6mm, half the length of internal crack is 6mm/2=3mm=0.003m

\sigma_c=\frac {K}{Y \sqrt {a\pi}}  and making K the subject

K=\sigma_c Y \sqrt {a\pi}  and substituting 260 MPa for \sigma_c  while a is taken as 0.003m and Y is already known

K=260*1.682*\sqrt {0.003*\pi}=42.455 Mpa

Therefore, fracture toughness at critical stress when maximum internal crack is 6mm is 42.455 Mpa and since it’s greater than 40 Mpa, fracture occurs to the material

6 0
3 years ago
Other questions:
  • You start your car and begin to pull out of a parking space. After leaving the space, You notice that the brake light on your in
    12·1 answer
  • 2. Write a Java program that generates a new string by concatenating the reversed substrings of even indexes and odd indexes sep
    10·1 answer
  • Write a C program that will update a bank balance. A user cannot withdraw an amount ofmoney that is more than the current balanc
    13·1 answer
  • 1.The moist unit weights and degrees of saturation of a soil are given: moist unit weight (1) = 16.62 kN/m^3, degree of saturati
    11·1 answer
  • The application of technology results in human-made things called
    9·1 answer
  • The following passage contains a fragment. Select the correct revision. Presley took the exuberance of gospel and added the freq
    7·1 answer
  • Two kilograms of air within a piston–cylinder assembly executes a Carnot power cycle with maximum and minimum temperatures of 80
    5·2 answers
  • B) Calculate the FS against uplift and calculate effoctive stress at the base level for water
    11·1 answer
  • A genetically engineered hormone.
    13·1 answer
  • Is Tesla French, American, German, or Russian?
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!