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natali 33 [55]
3 years ago
9

A field sample of an unconfined aquifer is packed in a test cylinder. The length and diameter of the cylinder are 50 cm and 6 cm

respectively. The field sample is tested for a period of three minutes under a constant head difference of 16.3 cm. As a result, 45.2 cm3 of water is collected at the outlet. Determine the hydraulic conductivity of the aquifer sample.

Engineering
1 answer:
Orlov [11]3 years ago
7 0

Answer:

0.09cm/sec

Explanation:

We are going to describe Hydraulic conductivity as a measure of the ease with which water flows through sediments, determining renewal rates of water, dissolved gases, and nutrients.

See attachment for a detailed solution.

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Answer:

Make sure both cars are in park or neutral with the parking brake engaged. This makes sure that all electrical functions (headlights, radios, etc.) are turned off.

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Identify 3 distractions for young drivers and explain how you plan to minimize these distractions
Veseljchak [2.6K]

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Phone, Eating, People in the car

Explanation:

your phone should always be off while driving and put away. Eating much like texting takes your attention away from the road so you should wait till you're parked or home to eat. People thrashing around or talking very loudly can be a terrible distraction. Ask them nicely to quiet down so you can focus on the road.

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A STANDARDIZED RECIPE WILL ALWAYS MAKE A CONSISTENT quality AND CONSISTENT
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Answer:

Quantity.

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3 years ago
If a toy car covers a distance of 42m in 7sec, what is it’s speed
S_A_V [24]

Answer:

6m/s

Explanation:

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Purely resistive loads of 24kW, 18kW and 12kW are connected between the neutral and the red, yellow and the blue respectively of
seraphim [82]

Answer:

The phase current in each line conductor are;

I_{R} = 100.17 < 0A

I_{Y} = 75.13< - 120A

I_{B} = 50.08

Explanation:

Given the following data;

Red phase = 24kW,

Yellow phase = 18kW

Blue phase = 12kW

Line voltage = 415V

For a star connected system, we have;

Phase voltage (V_{p} ) = \frac{Line voltage}{\sqrt{3}}

Phase voltage (V_{p} ) = \frac{415}{\sqrt{3}}

Phase voltage (V_{p} ) = 239.6V

The phase sequence for RYB is given by;

V_{R} = 239.6

Phase current (I) = \frac{Phase power}{Phase voltage}

Hence, I = \frac{P}{V}

<em>For the Red phase;</em>

I_{R} = \frac{24000}{239.6

I_{R} = 100.17 < 0A

<em>For the Yellow phase;</em>

I_{Y} = \frac{18000}{239.6

I_{Y} = 75.13< - 120A

<em>For the Blue phase;</em>

I_{B} = \frac{12000}{239.6

I_{B} = 50.08

For the line neutral;

I_{N} =\sqrt{ (I_{R}^{2} +I_{Y}^{2}+I_{B}^{2}-I_{R}I_{Y}-I_{Y}I_{B}-I_{R}I_{B}

Substituting we have, I_{N} = 43.29A

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3 years ago
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