Estimate the sum or difference...

xplain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that the

uranmaximum [27]

Answer: The interquartile range is preferred when the data are skewed or have outliers. An advantage of the standard deviation is that it uses all the observations in its computation.

Step-by-step explanation:

The interquartile range are resistant to outliers and can be used for data having glaring outliers.

Outliers are values that are too far away from the central value.

Interquartile range is a better option than standard deviation when there are a few extreme values and the distribution is skwed.

8 0

3 years ago

The following 5 questions are based on this information: An economist claims that average weekly food expenditure of households

liq [111]

Answer:

Null hypothesis: $\mu_{1}-\mu_{0}\leq 0$

Alternative hypothesis: $\mu_{1}-\mu_{2}>0$

$SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705$

b) 2.70

$t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850$

b. 1.85

$p_v =P(Z>1.85)=0.032$

b. 0.03

a. We can reject H(0) in favor of H(a)

Step-by-step explanation:

Data given and notation

$\bar X_{1}=164$ represent the mean for the sample 1

$\bar X_{2}=159$ represent the mean for the sample 2

$\sigma_{1}=12.5$ represent the population standard deviation for the sample 1

$s_{2}=9.25$ represent the population standard deviation for the sample B2

$n_{1}=35$ sample size selected 1

$n_{2}=30$ sample size selected 2

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the expenditure of households in City 1 is more than that of households in City 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{0}\leq 0$

Alternative hypothesis: $\mu_{1}-\mu_{2}>0$

We know the population deviations, so for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-0}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Standard error

The standard error on this case is given by:

$SE=\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}$

Replacing the values that we have we got:

$SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705$

b. 2.70

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850$

P-value

Since is a one side right tailed test the p value would be:

$p_v =P(Z>1.85)=0.032$

b. 0.03

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

a. We can reject H(0) in favor of H(a)

4 0

2 years ago

which of the following could be side lenths of a right triangle? A.) 0.9cm, 1.2cm, 1.5cm B.) 0.9cm, 1.5 cm, 1.5cm C.) 0.9 cm, 1.

Gwar [14]

Answer:

The answer A

Step-by-step explanation:

B: You need a side that is longer than 2 equal sides. B is incorrect.

A: Try

9^2 + 12^2 = 15^2 if that works, A will work.

81 + 144 = 225

This works. I used these numbers because they were easier to see.

0.9^2 + 1.2^2 = 1.5^2

0.81 + 1.44 = 2.25

2.25 = 2.25

That is the answer A

But we have to check the other two.

C:

0.9^2 = 0.81

1.2^2 = 1.44

1.8^2 = 3.24 This won't work. 3.24 is just too big.

D:

0.9^2 = 0.81

0.6^2 = 0.36

1.5^2 = 2.25 It's too far away.

5 0

2 years ago

James when to sleep at 9:10 he woke up at 9:45 how long was he sleep

horrorfan [7]

Answer:

35 minutes

Step-by-step explanation:

Take the lastest time and subtract the earliest time

9:45

9:10

------------

:35

35 minutes

8 0

3 years ago

Read 2 more answers

Regina’s work to find the surface area of a square pyramid from its net is shown below.

viva [34]

Answer:

The 3rd one

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers