The information in the table shows the possible genotypes resulting from the mating of two heterozygotes aadd. the allele a code
s for normal pigmentation, a for albinism, d for dimpled chin, and d for non-dimpled chin. what fraction of offspring would be expected to be albino with a non-dimpled chin? a. 1/2
b. 1/4
c. 3/4
d. 2/8
e. 1/16
Admitting that the "a" is a capital A for normal pigmentation and "d" is a capital D for dimpled chin, meaning that these are the dominant traits, the fraction expected to be albino with a non-dimpled chin is of 1/16. When two heterozygous are crossed and two characteristics are being analysed, the offspring quantity that will possess the two recessive traits can be represented by 1/16. This is easily confirmed when a Punnett square is made. Considering that both parents were heterozygous, on both sides of the crossing in the Punnett square, you would have the following alleles' combination: AD, Ad, aD, and ad. The offspring that would be homozygous recessive (aadd) would correspond to only 1/16.
I think the answer is D. ( or supported by observations ). Because theories change over time, they both NEED to be proven, they do NOT go off of consensus, but they do NEED to be supported by observations. I hope this helps.
