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4 years ago

Factor. 81x6−25y10 help asap please

Mathematics

2 answers:

Scrat [10]4 years ago

6 0

The answer is

486 - 250 y

ololo11 [35]4 years ago

5 0

Answer:

Step-by-step explanation:

81 x6−25y10 = 9²*(x³)² - 5²*(y⁵)²

= (9x³)² - (5y⁵)²

= (9x³ - 5y⁵) (9x³ + 5y⁵) { (a² - b²) = (a+b)(a-b) }

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A square garden has a diagonal of 12m. What is the perimeter of the garden? Express in simplest radical form.

FromTheMoon [43]

Answer:

24√2

Step-by-step explanation:

Let the side of the square be x

If the diagonal is 12m (hypotenuse), then;

x^2 + x^2 = 12^2

2x^2 = 144

x^2 = 144/2

x^2 = 72

x = √72

x = √36*2

x = 6√2

Perimeter of the square garden = 4x

Perimeter of the square garden = 4(6√2)

Perimeter of the square garden = 24√2

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3 years ago

Abby has 56 peppermints. Hugo has p fewer peppermints than Abby. Write an expression

Masteriza [31]

If the amount of peppermints Hugo has is represented by H:
56 - p = H
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6 0

3 years ago

A-B equals, if A =5x^2-4x-11 and B=-x^2+3x-5

Serga [27]

Answer:

A-B = 6x^2-7x-6

Step-by-step explanation:

A = 5x^2-4x-11

B = x^2+3x-5

A-B = (5x^2-4x-11) - (-x^2+3x-5) = 5x^2-4x-11+x^2-3x+5 = 6x^2-7x-6

8 0

2 years ago

A factory needs to produce 1,800 jars of peanut butter on a certain day.

RideAnS [48]

Answer:

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6 0

4 years ago

A sphere with a radius of 2 inches is inscribed in a right cone with a height of 6 inches. Find the surface area and the volume

Murljashka [212]

Answer:

Surface area of the cone $\approx 52 in^{2}$

Volume of the cone $\approx 25 in^{2}$

Step-by-step explanation:

Inscribing a sphere into a cone in simple terms, means placing the sphere into the circular base of the right cone, in such a way that the external circumference of the sphere just touches the internal circumference of the base of the cone.

The fact that inscription can occur perfectly, shows that the radius of the sphere and the base circle of the cone are equal.

Hence, we can obtain the dimensions of the cone as:

radius, r = 2 inches

height, h = 6 inches.

Surface area of the cone is got by the following formula:

$A = \pi r (r+ \sqrt{h^{2}+r^{2}})$

substituting in the values, we will have

$A = \pi \times 2 (2+ \sqrt{6^{2}+2^{2}})=52.304 in^{2} \approx 52in^{2}$

Volume of the cone =

$V= \pi r^{2}\frac{h}{3}$

substituting in the values, we will have

$V= \pi 2^{2} \times \frac{6}{3} =25.13 \approx 25in^{2}$

6 0

3 years ago