REAL NUMBER, RATIO NUMBER
Ok so any number tat makes the denomenator 0 or makes the inside of a square root negative is restricted
we only have a denomenaor so
100v=0
v=0
therefor 0 is the excluded value since 0/0 doesn't make sense
Hey,
2x^2 + 3root5x + 5
Here the product=10
And,sum=3root5
=>2x^2+2root5x+root5x+5
=>2x(x+root5)+ root5(x+root5)
=>(2x+root5)(x+root 5)
When you round you have to check the number to the right of the number you are rounding. If the number to the right is 0-4 then you keep the number the same. 5-9 the number you are rounding goes up by one. Now the 4 before the decimal point is in the ones spot. The 5 to the right of the 4 is the tenth spot and the 6 to the right of that is in the hundredth spot. so this is where we need to round. To the right of the 6 is a 4 so the number would stay the same. Now when you round you drop all the numbers after it so the number is 3184.56