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2 years ago

What is the place value of the number 5 in 2,257,926

Mathematics

2 answers:

Norma-Jean [14]2 years ago

8 0

Answer:

5 is in the ten thousands place.

Step-by-step explanation:

Since the number to the left of 5, 2, is in the hundred thousands place, and the number to the right, 7, is in the thousands place, 5 is in the ten thousands place.

I hope this helped! :-)

vesna_86 [32]2 years ago

5 0

Answer:

The number 5 is in the ten-thousands place.

Hope this helps!

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Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI

cricket20 [7]

Answer:

The system has infinitely many solutions

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

Switch any two rows
Multiply a row by a nonzero constant
Add one row to another

To solve the following system

$\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}$

Step 1: Transform the augmented matrix to the reduced row echelon form

$\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]$

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

The reduced row echelon form of the augmented matrix is

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

which corresponds to the system

$\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}$

The system has infinitely many solutions.

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

7 0

2 years ago

I need help on questions 48 49 and 50 and u need to find the surface area of the 3 polyhedras please and thank you!

White raven [17]

48. The surface area of a cylinder is given by

... A = 2πr² + 2πrh = 2πr(r+h)

For r = 13 mi and h = 7 mi, this becomes

... A = 2π(13 mi)(13 mi + 7 mi) = 520π mi²

The surface area of the cylinder is 520π mi² ≈ 1634 mi².

49. The surface area of a rectangular prism is

... A = 2(LW + H(L+W))

For L = 20 m, W = 10 m, H = 7 m, this becomes

... A = 2((20 m)(10 m) + (7 m)(20 m + 10 m)) = 2(200 m² + 210 m²) = 820 m²

The surface area of the prism is 820 m².

50. The formula is the same as for problem 48.

For r = 10 m and h = 13 m, this becomes

... A = 2π(10 m)(10 m + 13 m) = 460π m² ≈ 1445 m²

The surface area of the cylinder is 460π m² ≈ 1445 m².

_____

When calculations are repetitive, it is convenient to let a calculator or spreadsheet do them.

7 0

3 years ago

in abbys grade, there 70 students. currently, 10% of them are enrolled in health. how many students are enrolled in health?

goblinko [34]

Answer:

7 students.

Step-by-step explanation:

10% of 70 is 7.

4 0

2 years ago

The conversion rate for US Dollars to Costa Rican Colones is 1 USD = 518 Colones.

allsm [11]

The cost of 0.5 kg of bananas is 393.60 Colones as per the given conversion rates

Conversion rate of 1 USD to Costa Rican Colones = 518 Colones

The conversion rate of kg to pounds given in the question: 1 kg = 2.2025 lbs

Cost of one pound of bananas = $0.69

Bananas required to be purchased = 0.5kg

Converting 0.5kg bananas to pounds = 0.5*2.2025 = 1.10125 pounds

Cost of 1.10125 pound of bananas in dollars = 1.10125*0.69 = 0.7598

Cost of 1.1025 pounds of bananas in Colones = 0.7598*518 = 393.60 Colones

Hence, the cost is 393.60

Therefore, the cost of 0.5 kg bananas in Colones is 393.60 Colones

Learn more about conversion rate:

brainly.com/question/2274822

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5 0

5 months ago

Simplify 3^2×3^4×3^6

Dennis_Churaev [7]

The Answer is 513,441

4 0

2 years ago