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stiv31 [10]
2 years ago
8

The Venn diagram above represents the students who were sick one day in January at a Chicago high school. 80 students had only a

fever, 60 students had only a cough, 90 students had only a headache, 10 students had only a cough and fever, 30 students had only a cough and a headache, 40 students had only a fever and a headache, and 20 students had a fever, cough, and headache. 100 students had other reasons for being absent that day. None of the sick students attended school that day. If 800 students attend the high school, how many students were at school that day?
Mathematics
1 answer:
mrs_skeptik [129]2 years ago
5 0

Answer:

370

Step-by-step explanation:

The venn diagram corresponds to students who were sick in January at a Chicago high school.

Students who had only fever= n(A) = 80

Students who had only headache= n(B) = 90

Students who had only cough  = n(C) =60

Students who had both cough and fever = n(AC) = 10

n(AB) = 40:n(BC) = 30  n(ABC) = 20

Hence total students = 800

no of students who were absent due to other reasons = 100

REmaining students = 700

Students who were sick = sum of all =330

So no of students who were at school = 700-330 = 370

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Answer: Probability that this whole shipment will be accepted is 0.629

Step-by-step explanation:

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Applying normal distribution,

z = (x-u)/s

Where

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s = standard deviation

u = mean = np

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q = probability that the component does not have defect

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From the information given,

p = 8/100 = 0.08

q = 1-q = 1-0.08 = 0.92

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u = 20×0.08 = 1.6

s = √20 × 0.08 × 0.92 = √1.472

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Probability that this whole shipment will be accepted will be probability that fewer than 3 components have defects. This means that it must be lesser than or equal to 2 components.

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8 0
3 years ago
[Angles question]
11111nata11111 [884]
Here is my friendly solution i'll skip the proof part for now. I am working on the others.

8 0
3 years ago
Lesson Posttest
stepladder [879]

Answer:

1

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The probability of drawing an apple is P(orange) = number of oranges/total number of fruit = 5/19

The probability of drawing either an apple, peach or orange at the first draw of fruit from the bag is

P(apple or peach or orange) =  P(apple) + P(peach) + P(orange)

                                               = 5/19 + 9/19 + 5/19

                                               = (5 + 9 + 5)/19

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                                               = 1

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3 years ago
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Answer:

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