The values of x and y that satisfy this system of equations are 10 and 5 respectively
<h3>Simultaneous equation</h3>
Given the system of equations
x + y = 20
3x - 3y = 30
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x + y = 20
x - y = 10
Add the equations
2x = 20 + 10
2x = 30
x = 30/2
x = 15
Substitute
x -y = 10
15 - y = 10
y = 5
Hence the values of x and y that satisfy this system of equations are 10 and 5 respectively
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Answer:
If A = {1,20,30..} and B = {4,6} find n(A-B)?
The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using

Substitute the known values in the above equation

Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Step-by-step explanation:
HCF of 60 and 84 = 6
So the required greatest number that divides 60 and 84 without leaving remainder is 6.