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romanna [79]
3 years ago
15

The length of a rectangle is four more than three times the width. If the perimeter of this rectangle is at least 70 square cent

imeters. Write an inequality that can be solved to find the width of the rectangle.
Mathematics
1 answer:
FrozenT [24]3 years ago
7 0

Answer:

Step-by-step explanation:

Let L represent the length of the triangle.

Let W represent the width of the triangle.

The length of a rectangle is four more than three times the width. This means that

L = 3W + 4

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

If the perimeter of this rectangle is at least 70 square centimeters, an inequality that can be solved to find the width of the rectangle is

2(L + W) ≥ 70

L + W ≥ 70/2

L + W ≥ 35

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The value of 3b2 – b when b = 5
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Answer:

70

Step-by-step explanation:

Evaluate 3 b^2 - b where b = 5:

3 b^2 - b = 3×5^2 - 5

Hint: | Evaluate 5^2.

5^2 = 25:

3×25 - 5

Hint: | Multiply 3 and 25 together.

3×25 = 75:

75 - 5

Hint: | Subtract 5 from 75.

| 7 | 5

- | | 5

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Answer:  70

6 0
3 years ago
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K.E=0.5mv^2
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The child has both K.E and GPE
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3 years ago
What is bigger 1/3 or 3/5
raketka [301]

Method\ 1:

\dfrac{1}{3}=\dfrac{1\cdot5}{3\cdot5}=\dfrac{5}{15}\\\\\dfrac{3}{5}=\dfrac{3\cdot3}{5\cdot3}=\dfrac{9}{15}\\\\\dfrac{3}{15} < \dfrac{9}{15}\ therefore\ \dfrac{3}{5}\ is\ bigger


Method\ 2:

\dfrac{1}{3} < \dfrac{1}{2}=\dfrac{1.5}{3}\\\\\dfrac{3}{5} > \dfrac{1}{2}=\dfrac{2.5}{5}\\\\therefore\ \dfrac{3}{5}\ is\ bigger

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Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

4 0
3 years ago
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