Answer: 11am
Step-by-step explanation:
To solve this, we have to calculate the lowest common multiple of 20 and 30. This will be:
20 = 20, 40, 60, 80, 100
30 = 30, 60, 90, 120, 150.
Here, the lowest common multiple is 60.
Therefore, we add 60 minutes to 10am. This will be:
= 10am + 1 hour
= 11 am
The next time that both buses leave at the same time would be 11am
This is a question of proportions:
First we can work out how many feet it goes up for each feet he steps back:
5.5/6 ft per each feet he steps back.
Now we can multiply this by the amount of ft back the cliff is:
(5.5/6)*30 = 27.5 ft
Thus the cliff is 27.5 ft tall,
Hope this helps :)
A reasonable estimate would be 180 students with blue eyes
Answer:
Average speed is 37.35 mi/h
Step-by-step explanation:
given data
leave = 34 minutes before
church distance = 12.0 miles
average speed first 17 minutes = 5.0 mi/h
solution
so we find Total distance travel in first 17 minutes = speed × time
Total distance travel in first 17 minutes = 5 × 
Total distance travel in first 17 minutes = 1.416 mi
and
Distance Remaining = 12 - 1.416 = 10.584 mi
Time Remaining = 34 - 17 min = 17 min
so
remaining distance Average speed =
Average speed =
Average speed is 37.35 mi/h
Answer:
UB: 375
Step-by-step explanation:
370mm to 2 sig figs..
UB: 375
LB:365
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