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swat32
4 years ago
10

Consider the following vector-valued function:~h(t) =〈2 sin(3t),3 cos(3t),√5 sin(3t)〉0≤t≤2π3This defines a smooth parameterized

curve.(a) Find the unit tangent vector~T(t) for 0≤t≤2π3.(b) Find all of the values oftin the interval 0≤t≤2π3where~h(t) and~T(t) areorthogonal.(c) Show that the curve~h(t) lies on a sphere. What is the radius of the sphere?

Mathematics
1 answer:
omeli [17]4 years ago
5 0

Answer:

a) h'(t)= (6cos3t,-9sin3t,3\sqrt[]{5}cos3t)

b) t=0.93994736+πn/3

c) Magnitude of h(t) is 3 which is a constant, so h(t) lies on a sphere

Step-by-step explanation:

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Substitution:
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d u = 1/x² dx
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8 0
3 years ago
Write the equation of the line that passes through the points (8, -4) and (-2,5).
Sladkaya [172]

Answer:

The equation in the slope-intercept form will be:

Step-by-step explanation:

Given the points

  • (8, -4) and (-2, 5)

The slope between two points

m=\frac{5-\left(-4\right)}{-2-8}

m=-\frac{9}{10}

As the point-slope form is

y-y_1=m\left(x-x_1\right)

substituting the values m = -9/10 and (8, -4)

y-\left(-4\right)=-\frac{9}{10}\left(x-8\right)

Writing the line equation in the slope-intercept form

y=mx+b

where m is the slope and b is the y-intercept

so the equation in the slope-intercept form will be:

y-\left(-4\right)=-\frac{9}{10}\left(x-8\right)

y+4=-\frac{9}{10}\left(x-8\right)

subtract 4 from both sides

y+4-4=-\frac{9}{10}\left(x-8\right)-4

y=-\frac{9}{10}x+\frac{16}{5}

Therefore, the equation in the slope-intercept form will be:

y=-\frac{9}{10}x+\frac{16}{5}

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B7%7D%20" id="TexFormula1" title=" \sqrt{7} " alt=" \sqrt{7} " align="absmiddle" c
Radda [10]

Answer:  \frac{\sqrt{7}}{7}

========================================================

Explanation:

The reciprocal of x is 1/x where x is nonzero. Multiplying x with 1/x leads to 1. For example, the numbers 9 and 1/9 are multiplicative inverses of each other.

We'll stick 1 over the given square root expression. Then follow these steps to rationalize the denominator.

\frac{1}{\sqrt{7}}\\\\\\\frac{1*\sqrt{7}}{\sqrt{7}*\sqrt{7}}\\\\\\\frac{\sqrt{7}}{(\sqrt{7})^2}\\\\\\\frac{\sqrt{7}}{7}\\\\

In short, \frac{1}{\sqrt{7}}=\frac{\sqrt{7}}{7}

4 0
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What number is 1/4 of 100
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3 years ago
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VladimirAG [237]
-0.1 is your answer <3
4 0
3 years ago
Read 2 more answers
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