Given coordinates of the endpoints of a line segment (5,-9) and (1,3).
In order to find the equation of perpendicular line, we need to find the slope between given coordinates.
Slope between (5,-9) and (1,3) is :
Slope of the perpendicular line is reciprocal and opposite in sign.
Therefore, slope of the perpendicular line = 1/3.
Now, we need to find the midpoint of the given coordinates.
Let us apply point-slope form of the linear equation:
y-y1 = m(x-x1)
y - (-3) = 1/3 (x - 3)
y +3 = 1/3 x - 1
Subtracting 3 from both sides, we get
y +3-3 = 1/3 x - 1 -3
<h3>
y = 1/3 x - 4 .</h3>
The slope of the line is three
240 because <span>The multiples of 15 are ... , 225, 240, 255, ....and t<span>he multiples of 16 are ..., 224, 240, 256, ...</span></span>
Here is the correct format for the question
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acceleration is exactly 80 mi/h².Let v(f) be the velocity of the car t hours after 2:00 PM.Then 
. By the Mean Value Theorem, there is a number c such that 0 < c < 
with v'(c) = . Since v'(t) is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 80 mi/h^2.
Answer:
Step-by-step explanation:
From the information given :
At 2:00 PM ;
a car's speedometer v(0) = 30 mi/h
At 2:15 PM;
a car's speedometer v(1/4) = 50 mi/h
Given that:
v(f) should be the velocity of the car t hours after 2:00 PM
Then will be:
= 20 × 4/1
= 80 mi/h²
By the Mean value theorem; there is a number c such that :
with 
