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Digiron [165]
3 years ago
7

A motherboard uses dual channeling, but you have four DIMMs available that differ in size. The motherboard supports all four siz

es. Can you install these DIMMs on the board? Will dual channeling be enabled?
Computers and Technology
1 answer:
Andru [333]3 years ago
7 0

Answer:

Explanation:

We can install four DIMMs with different size, for example if we want 1 GB, 2 GB, 4 GB, and 8 GB, in this example every DIMM are different, but we can install these DIMMs in our motherboard, but the dual channeling, in this case is not enabled, because DIMMs must be with the same size, frequency, latency, and even model, and nowadys there is quad channeling.

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A large retail company hires several new joiners and would like to incorporate Virtual Reality (VR) into their onboarding proces
Volgvan

 The best utilize VR for this purpose is a simulated experience interacting with customers.

<h3>What is Virtual reality (VR)?</h3>

Virtual Reality (VR) is known to be a kind of computer created environment that is made up of scenes and objects that seems to be real.

It is a type of reality that makes its  user feel they are inside their surroundings. This environment is said to be seen via device known as a Virtual Reality headset or helmet.

See options below

Which approach would best utilize VR for this purpose?

an animated video that covers compliance training

a 360-degree online tour of the retail store

an application that enables online contract signing

a simulated experience interacting with customers

Learn more about Virtual Reality (VR) from

brainly.com/question/26705841

4 0
2 years ago
Novice drivers lack the experience necessary to reliably categorize and appropriately respond to ___________ hazards.
meriva

Answer:

roadside

Explanation:

Novice drivers lack the experience necessary to reliably categorize and appropriately respond to roadside hazards. A roadside hazard refers to any roadside objects or features that have a diameter greater than 100mm that is on or near the roadway. These are objects or features that are likely to create a dangerous environment to the drivers.

7 0
3 years ago
a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv
Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that  cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em>// chracter to digit mapping, and the inverse</em>

<em>// (if you want better performance: use array instead of unordered_map)</em>

<em>unordered_map<char, int> c2i;</em>

<em>unordered_map<int, char> i2c;</em>

<em>int ans = 0;</em>

<em>// limit: length of result</em>

<em>int limit = 0;</em>

<em>// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]  </em>

<em>bool helper(vector<string>& words, string& result, int digit, int widx, int sum) { </em>

<em>    if (digit == limit) {</em>

<em>        ans += (sum == 0);</em>

<em>        return sum == 0;</em>

<em>    }</em>

<em>    // if summation at digit position complete, validate it with result[digit].</em>

<em>    if (widx == words.size()) {</em>

<em>        if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {</em>

<em>            if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result</em>

<em>                return false;</em>

<em>            c2i[result[digit]] = sum % 10;</em>

<em>            i2c[sum%10] = result[digit];</em>

<em>            bool tmp = helper(words, result, digit+1, 0, sum/10);</em>

<em>            c2i.erase(result[digit]);</em>

<em>            i2c.erase(sum%10);</em>

<em>            ans += tmp;</em>

<em>            return tmp;</em>

<em>        } else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){</em>

<em>            if (digit + 1 == limit && 0 == c2i[result[digit]]) {</em>

<em>                return false;</em>

<em>            }</em>

<em>            return helper(words, result, digit+1, 0, sum/10);</em>

<em>        } else {</em>

<em>            return false;</em>

<em>        }</em>

<em>    }</em>

<em>    // if word[widx] length less than digit, ignore and go to next word</em>

<em>    if (digit >= words[widx].length()) {</em>

<em>        return helper(words, result, digit, widx+1, sum);</em>

<em>    }</em>

<em>    // if word[widx][digit] already mapped to a value</em>

<em>    if (c2i.count(words[widx][digit])) {</em>

<em>        if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0) </em>

<em>            return false;</em>

<em>        return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);</em>

<em>    }</em>

<em>    // if word[widx][digit] not mapped to a value yet</em>

<em>    for (int i = 0; i < 10; i++) {</em>

<em>        if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;</em>

<em>        if (i2c.count(i)) continue;</em>

<em>        c2i[words[widx][digit]] = i;</em>

<em>        i2c[i] = words[widx][digit];</em>

<em>        bool tmp = helper(words, result, digit, widx+1, sum+i);</em>

<em>        c2i.erase(words[widx][digit]);</em>

<em>        i2c.erase(i);</em>

<em>    }</em>

<em>    return false;</em>

<em>}</em>

<em>void isSolvable(vector<string>& words, string result) {</em>

<em>    limit = result.length();</em>

<em>    for (auto &w: words) </em>

<em>        if (w.length() > limit) </em>

<em>            return;</em>

<em>    for (auto&w:words) </em>

<em>        reverse(w.begin(), w.end());</em>

<em>    reverse(result.begin(), result.end());</em>

<em>    int aa = helper(words, result, 0, 0, 0);</em>

<em>}</em>

<em />

<em>int main()</em>

<em>{</em>

<em>    ans = 0;</em>

<em>    vector<string> words={"GREEN" , "BLUE"} ;</em>

<em>    string result = "BLACK";</em>

<em>    isSolvable(words, result);</em>

<em>    cout << ans << "\n";</em>

<em>    return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0
2 years ago
2-3 Calculating the Body Mass Index (BMI). (Programming Exercise 2.14) Body Mass Index is a measure of health based on your weig
Luden [163]

Answer:

weight = float(input("Enter your weight in pounds: "))

height = float(input("Enter your height in inches: "))

weight = weight * 0.45359237

height = height * 0.0254

bmi = weight / (height * height)

print("Your BMI is: %.4f" % bmi)

Explanation:

*The code is written in Python.

Ask the user to enter weight in pounds and height in inches

Convert the weight into kilograms and height into meters using given conversion rates

Calculate the BMI using given formula

Print the BMI

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3 years ago
What is a segment
monitta
A length of uninterrupted cable connecting two devices
3 0
3 years ago
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