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Digiron [165]
3 years ago
7

A motherboard uses dual channeling, but you have four DIMMs available that differ in size. The motherboard supports all four siz

es. Can you install these DIMMs on the board? Will dual channeling be enabled?
Computers and Technology
1 answer:
Andru [333]3 years ago
7 0

Answer:

Explanation:

We can install four DIMMs with different size, for example if we want 1 GB, 2 GB, 4 GB, and 8 GB, in this example every DIMM are different, but we can install these DIMMs in our motherboard, but the dual channeling, in this case is not enabled, because DIMMs must be with the same size, frequency, latency, and even model, and nowadys there is quad channeling.

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What is one of the main problems with shared web hosting? Select one: Sites that share resources are less susceptible to hacking
Pani-rosa [81]

Answer:

If one or more of the shared sites go down, then there is a good chance that your site will go down as well.

Explanation:

Shared web hosting is a form of web hosting service whereby more than one websites are placed on a single web server that connects to the internet.

Though it is cheaper, it has various problems. And over time, it has been concluded that the major problem associated with shared web hosting is the security issue.

This implies that "If one or more of the shared sites go down, then there is a good chance that your site will go down as well."

Some other problems associated with Shared web hosting are poor value, less flexibility, none advanced features, slow service, less support.

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3 years ago
Input is information a system uses to monitor and adjust itself to meet the goal.
agasfer [191]
That is a true statement. Hope this was helpful!
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3 years ago
Consider the latency model for static congestion windows. If the server receives an acknowledgement for the first data segment i
Angelina_Jolie [31]

Answer:

Latency of an object O is shown below.

Explanation:

W segment and stalled state transmits nothing and waits for acknowledgement. The latency is 2 R TT + the time required for server that are using to transmit the object + the amount of time when server is in stalled state. Let K be the number of window that is K= O/WS .The serveries stalled state where K-1 is period of ime with period lasting RTT-(W-1)S/R

latency = 2RTT +O/R +(K-1)[S/R +RTT - WS/R]

After combining the two case

latency = 2 RTT + O/R + (K-1)[S/R +RTT - WS/R]

where [x] means maximum of (x.0). This is the complete ananlysis of the static windows.

server time for transmit the object is (K-1)[S/R +RTT - WS/R]

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garik1379 [7]

Answer:

a string

Explanation:

bcz that's the only answer

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