Find the greatest common factor of 27 and 45

Mathematics

1 answer:

AlladinOne [14]3 years ago

7 0

Answer:

the anwser is 9

Step-by-step explanation:

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Find the value of this expression if x = -6.<br> x^2-3/x+3<br> Enter the correct answer.

Amanda [17]

Answer:

$\frac{x^{2}-3}{x+3}=\frac{(-6)^{2}-3}{-6+3}\\\\=\frac{36-3}{-3}=\frac{33}{-3}=-11$

Step-by-step explanation:

6 0

3 years ago

Find the rate of change given the following solutions: (6, 2) and (1, 12).

blagie [28]

Answer:

The rate of change is -2

Step-by-step explanation:

f(b)-f(a) 12-2 10

---------- = ------------ = -------- = -2

b-a 1-6 -5

7 0

3 years ago

In 1982 Abby’s mother scored at the 93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the

oksian1 [2.3K]

Answer:

The percentle for Abby's score was the 89.62nd percentile.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation(which is the square root of the variance) $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Abby's mom score:

93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.

93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

$\mu = 503, \sigma = \sqrt{9604} = 98$