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Andru [333]
3 years ago
10

9x2 − 16x + 60 = 0

Mathematics
1 answer:
Anton [14]3 years ago
3 0
A. that is b^2-4ac
for
ax^2+bx+c
the deterimant (part under the radicand)
is b^2-4ac
if it is
1. less than 0 then there are no real solutions
2. eqal to 0 then there is 1 real solution
3. greater than 0, there are 2 real roots
9x^2-16x+60
b^2-4ac=(-16)^2-4*9*60=256-2160<0
no real solutions




B. grouping
ac method
4 times -5=-20
what 2 numbers multiply to get -20 and add to get 8?
-2 and 10
seperate the middle number to get that
4x^2-2x+10x-5=0
(4x^2-2x)+(10x-5)=0
2x(2x-1)+2(2x-1)=0
(2x-1)(2x+2)=0
set equal to 0

2x-1=0
2x=1
x=1/2

2x+2=0
2x=-2
x=-1

x=1/2 or -1
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The admission prices for a small fair are $1.50 for children and $4.00 for adults. In one day there was $5050 collected. If we k
aliina [53]

Answer: 475 adults paid admission

Step-by-step explanation:

1.50c+4a=5050 (1.50 per child and 4 per adult)

1.50(2100)+4c=5050 (2100 children times 1.5 each)

3130+4a=5050

4a=1900

a=475

3 0
3 years ago
2. In the diagram below, secants PT and PU have been drawn from exterior point P such that the four arcs
scoundrel [369]

Answer:

(a) x = 30°

(b) mRS =  30°

mST =  120°

mTU  = 120°

mUR = 90°

Step-by-step explanation:

(a) In the picture attached, the diagram is shown.

Given that m arc RS = x, from the ratios:

m arc ST = 4x

m arc TU = 4x

m arc UR = 3x

The addition of the four arcs must be equal to 360°, then:

x + 4x + 4x + 3x = 360°

12x = 360°

x = 360°/12 = 30°

(b) m arc RS = x = 30°

m arc ST = 4x = 4*30° = 120°

m arc TU = 4x = 4*30° = 120°

m arc UR = 3x = 3*30° = 90°

8 0
3 years ago
A bag is filled with green and blue marbles. There are 125 marbles in the bag. If there are 29 more green
ValentinkaMS [17]

Answer:

89 green marbles and 46 blue marbles

Step-by-step explanation:

3 0
2 years ago
Subtract (x^2+3x-4) -(4x-2x^2-3)
Feliz [49]

Answer:

3 x^2 - x + -1

Step-by-step explanation:

Simplify the following:

-(4 x - 2 x^2 - 3) + x^2 + 3 x - 4

Factor -1 out of -2 x^2 + 4 x - 3:

--(2 x^2 - 4 x + 3) + x^2 + 3 x - 4

(-1)^2 = 1:

2 x^2 - 4 x + 3 + x^2 + 3 x - 4

Grouping like terms, 2 x^2 + x^2 + 3 x - 4 x - 4 + 3 = (x^2 + 2 x^2) + (3 x - 4 x) + (-4 + 3):

(x^2 + 2 x^2) + (3 x - 4 x) + (-4 + 3)

x^2 + 2 x^2 = 3 x^2:

3 x^2 + (3 x - 4 x) + (-4 + 3)

3 x - 4 x = -x:

3 x^2 + -x + (-4 + 3)

3 - 4 = -1:

Answer: 3 x^2 - x + -1

4 0
3 years ago
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After you solve it you get B

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