In parallelogram LMNO, NO = 10.2, and LO = 14.7. The basic property of a parallelogram that the opposite sides in a parallelogram are equal; so, two sides are 10.2 (NO=LM=10.2), and two sizes are 14.7, = (LO=MN=14.7).
The perimeter of the parallelogram LMNO is:
P= 2NO + 2LO.
P= (2 x 10.2)+(2 x 14.7).
P= 20.4 + 29.4.
So, P= 49.8.
Answer:
2x + 3y = 6
Step-by-step explanation:
There is about 87658.1. there are 8765.81 in one year so multiply by ten to get 87658.1.
AB = CB
Because they are congruent
Therefore CB = 5.9
Given perimeter = 17
CB+BE+ED+DC = 17
5.9 + BE + 2.8 + 5.6 = 17
BE + 14.3 = 17
BE = 17 - 14.3
= 2.7
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Part A:
<span>a system of inequalities that only contain points D and E in the overlapping shaded regions is
5y + 2x > 12
2y - x < 12
Part B:
To verify that points D and E are solutions to the system of inequalities, we plug in the coordinate points of points D and E into the system of ineaqualities.
Part C:
</span>To <span>identify the schools that Timothy is allowed to attend we plug in the coordinate values of the points to see which satisfies the inequality y < 3x - 3. Thus Timothy is allowed to attend schools C and F.</span>
