Solution:
4.2 x 10^6 bp/10^3 bp/seconds = 4.2 + 103 s which is 4200 seconds and equivalents to 70 minutes
In addition, assuming a pause of 2 seconds for re initiating after completing every okazaki fragment and assuming the okazaki fragments average 1000 nucleotide long.
4.2 x 10^6 bp/10^3 bp = 4200 okazaki fragments 4200 * 2 seconds = 8400 seconds which is 140 minutes or 2 hours 20 minutes of pauses alone.
Therefore, overall time would be pauses plus the 70 minutes so total time of 210 minutes. Assuming that the replisome completely disassociates from the DNA after every okazaki fragment and must spend one-minute rebinding.
4200 okazaki fragments. 60 seconds rebinding time per fragment: 4200 x 1 minute = 4200 minutes rebinding time plus 70 minutes for actual replication. 4200 minutes is 70 hours which is almost 3 days.
Answer:
This question lacks options, the options are:
a) Negative primary production
b) Net primary production
c) Secondary production
d) Negative secondary production
e) Positive primary production
The correct answer is b.
The total amount of chemical energy produced by autotrophs, such as plants and phytoplankton, is called gross primary production. The energy that remains after plants use some of the gross primary production to fuel their own metabolism is known as <u>net primary production</u>.
Explanation:
Net Primary Production (NPP) is the value that results from the difference between gross production and respiration of the primary producers themselves. It manifests as growth and / or reproduction. It represents the matter and energy available for the next trophic level, that is, the net primary production is what is left after subtracting the energy that plants use for their metabolism or maintenance (such as breathing, tissue construction and reproduction).
Answer:
A) parietal cells
Explanation:
Parietal cells are the epithelial cells of the stomach that have the function to secrete hydrochloric acid (HCl) and intrinsic factor. Parietal cells contain canaliculi – secretory network for the secretion of HCl via active transport.
Parietal cells are regulated via several factors such as acetylcholine, gastrin and histamine. So, if histamine receptors are blocked via antacid drugs , the secretion of the acid will be reduced.
There are chances of 75% solid green coloured rind in watermelons.
Explanation:
Dominant trait = Solid Green rind G
Recessive trait= stripes g
Given that both the parent plants are heterozygous so their alleles will be
Gg Gg
From the Punnet square
G g
G GG Gg
g Gg gg
The phenotype ratio is 3:1 ( 3 watermelons with the green colour rind and 1 with striped rind observed)
Genotype ratio is 1:2:1
From the observation, we can say that 75% of the watermelons will have solid green colour rind because G is dominant over g.
