Ask question

Ask question

All categories

4 years ago

13

En la expresion algebraica x², ¿que indica el número 2 en la base x?

1 answer:

tino4ka555 [31]4 years ago

5 0

Answer:

En la expresión, 2 representa la cantidad de veces que multiplicas x por sí mismo.

**Lo siento si mi español es malo, el inglés es mi primer idioma.

Step-by-step explanation:

$8^{2}$ = 8 × 8 = 64

$y^2$ = y × y

You might be interested in

The function shown in the graph is shifted 4 units up to produce a

LuckyWell [14K]

Answer: D

Step-by-step explanation:

6 0

3 years ago

The perimeter of a rectangle is 24 feet. The length is 3 feet less than twice the width. Which of the following systems is corre

Anna007 [38]

Answer:

The answer is B.)

Step-by-step explanation:

Because, 5 x 2 = 10 and 10 - 3 = 7 .

7 0

3 years ago

Can you please help with this question about exponential equations?

RSB [31]

Since $t$ represents the number of years passed since 2005, in 2005 we have $t=0$ , and in 2015 we have $t=10$ . Let $P_J(y),P_D(y)$ represent the profits of Jones and Davis, respectively, at year y.

We have

$P_J(2005) = 10(0.99)^0 = 10,\quad P_J(2015) = 10(0.99)^{10}\approx 9$

$P_D(2005) = 8(1.01)^0 = 8,\quad P_D(2015) = 8(1.01)^{10}\approx 9$

Choosing the best company somehow depends on how much time you can wait: Jones start with a higher value (10 vs 8), but it has a descending trend, because the multiplicative factor $0.99^t$ goes to zero as t grows.

On the other hand, Davis starts with a smaller value, but $1.01^t$ tends to infinity as t grows.

So, if you need an immediate result, the most valuable company is Jones, otherwise you're certain can Davis will eventually become bigger.

More precisely, we have

$8\cdot 1.01^t = 10\cdot 0.99^t \iff 0.8 = \left(\dfrac{0.99}{1.01}\right)^t \iff t\approx 11$

So, after 11 years, Davis will overcome Jones.

3 0

3 years ago

Prove that tan 10+tan 70'+taniou = tanio tanfo'tam 1oo.

Galina-37 [17]

Question:

Prove that:

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Answer:

Proved

Step-by-step explanation:

Given

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Required

Prove

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$

Subtract tan(10) from both sides

$- tan(10)+tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)$

$tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)$

Factorize the right hand size

$tan(70) + tan(100) = -tan(10)(-tan(70). tan(100) + 1)$

Rewrite as:

$tan(70) + tan(100) = -tan(10)(1-tan(70). tan(100))$

Divide both sides by $1-tan(70). tan(100)$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = \frac{-tan(10)(1-tan(70). tan(100))}{1-tan(70). tan(100))}$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)$

In trigonometry:

$tan(A + B) = \frac{tan(A) + tan(B)}{1 - tan(A)tan(B)}$

So:

$\frac{tan(70) + tan(100)}{1 - tan(70)tan(100)}$ can be expressed as: $tan(70 + 100)$

$\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)$ gives

$tan(70 + 100) = -tan(10)$

$tan(170) = -tan(10)$

In trigonometry:

$tan(180 - \theta) = -tan(\theta)$

So:

$tan(180 - 10) = -tan(10)$

Because RHS = LHS

Then:

$tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)$ has been proven

6 0

3 years ago

Find measure of angles B, E, D and C and the length of BC.

natulia [17]

Answer:

< B = 180-30-65=85°

< E = 85°

< D = 30°

< C = 65°

BC = 20/35 × 28 = 16

5 0

3 years ago

Read 2 more answers