Answer:
Step-by-step explanation:
They are just asking you to compare
to
.
What constant values are in the place of 
.
Answer:
- A, D, E, F, H, I, M, N, O, R, S, T, U, W, Y
Explanation:
Order the letters of each day, omitting the repetitions:
MONDAY:
TUESDAY:
WEDNESDAY:
THURSDAY:
FRIDAY:
SATURDAY:
SUNDAY:
Put the letters together:
- A, D, M, N, O, Y, A, D, E, S, T, U, Y, A, D, E, N, S, W, Y, A, D, H, R, S, T, U, Y, A, D, F, I, R, Y, A, D, R, S, T, U, Y, A, D, N, S, U, Y
Delete the repetitions:
- A, D, M, N, O, Y, E, S, T, U, W, H, R, F, I.
Reorder:
- A, D, E, F, H, I, M, N, O, R, S, T, U, W, Y ← answer
20 Cubic Inches^3.
Explanation:
The volume of a cone is Pi*R^2*H*1/3
We know the height, but we are given the diameter instead of radius. So divide 5.625 by 2. You get 2.8125.
Plug everything into the formula.
Pi*2.8125^2*7.5*1/3
(The ^2 means squared, or to the second power)
You get a number close to 20. Since we don’t know Pi, and we are not given a substitute for Pi, we make the answer in terms of Pi.
20 Cubic Inches^3.
Also, people who don’t know the answers to questions shouldn’t just put a random answer for the points. It’s unfair.
Answer:
![12-[20-2(6^2\div3\times2^2)]=88](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%3D88)
Step-by-step explanation:
So we have the expression:
![12-[20-2(6^2\div3\times2^2)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D)
Recall the order of operations or PEMDAS:
P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.
E: Within the parentheses, if exponents are present, do them before all other operations.
M/D: Multiplication and division next, whichever comes first.
A/S: Addition and subtraction next, whichever comes first.
(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)
Thus, we should do the operations inside the parentheses first. Therefore:
The parentheses is:
Square the 6 and the 4:
Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:
Therefore, the original equation is now:
![12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]](https://tex.z-dn.net/?f=12-%5B20-2%286%5E2%5Cdiv3%5Ctimes2%5E2%29%5D%5C%5C%3D12-%20%5B20-2%2848%29%5D)
Multiply with the brackets:
![=12-[20-96]](https://tex.z-dn.net/?f=%3D12-%5B20-96%5D)
Subtract with the brackets:
![=12-[-76]](https://tex.z-dn.net/?f=%3D12-%5B-76%5D)
Two negatives make a positive. Add:
Therefore:
First you would have to turn the mixed number into a improper fraction. to do that you would have to multiply the denominator by the 1 (which is the whole number) to get 3*1=3 then you would have to add the numerator to get 3+2=5. now you have an improper fraction which is now 5/3. you always keep the denominator the same. next you have to multiply the two fractions you now have. which is 5 over 3 and 3 over 4 . all you have to do is multiply across to get 5*3=15 on the top and 3*4=12 on the bottom. so your new fraction you have is 15/12. that's an improper fraction so you would have to divide 12 by 15. you know 12 goes into 15 one time with a remainder of 3. so now you have 1 3/12 as your answer. but your not done yet. now you have to simplify your answer by dividing the numerator and denominator by 3 to get 3/3=1 and 12/3=4, you final answer should be 1 1/4 .
