Monica took a survey of her classmates' hair and eye color. The results are in the table below.
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T<span>he mean of a sampling distribution of a sample with proportion, p and sample size, n is given by 
.
</span>T<span>he standard deviation of a sampling distribution of a sample with proportion, p and sample size, n is given by
</span>Given that t<span>he manufacturers of m&m's claim that 20% of the milk chocolate m&m candies are orange. The proportion is p = 0.2
The mean of the sampling distribution of the sample proportion of orange m&m's for samples of size 100 is given by
</span><span>The standard deviation of the sampling distribution of the sample proportion of orange m&m's for samples of size 100 is given by
</span>
</span>T<span>he standard deviation of a sampling distribution of a sample with proportion, p and sample size, n is given by
</span>Given that t<span>he manufacturers of m&m's claim that 20% of the milk chocolate m&m candies are orange. The proportion is p = 0.2
The mean of the sampling distribution of the sample proportion of orange m&m's for samples of size 100 is given by
</span><span>The standard deviation of the sampling distribution of the sample proportion of orange m&m's for samples of size 100 is given by
Given parameters:
Mark up percentage = 150%
Original cost = $488
Sales tax = 5%
Unknown:
His total cost = ?
Solution:
Marking up a good is the amount a sell adds to a product which makes its selling price usually for a profit.
Since the emerald was marked up by 150%;
New cost = (1 + 1.5) x $488 = $1220
Now, the additional tax was 5%;
Tax = x 1220 = $61
So, the total cost = New cost + tax = $1220 + $61 = $1281