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Hitman42 [59]
3 years ago
13

All of the following are career pathways in the architecture and construction career cluster except

Computers and Technology
2 answers:
ololo11 [35]3 years ago
8 0

Answer:

Power, Structural, and Technical Systems

Explanation:

Apex (-:

max2010maxim [7]3 years ago
3 0

Below, I believe are the multiple choices attached to this question

A. Power, Structural, and Technical Systems.

B. Construction.

C. Design/ Pre-Construction.

D. Maintenance/ Operations

The answer is A. Power, Structural, and Technical Systems.

The career pathways in the Architecture and Construction deal with all aspects of designing, planning, maintaining all kinds of structures we live or work in. It is organized into 3 career pathways; Construction, Design/ Pre-Construction, and Maintenance/ Operations. This field also covers the servicing of equipment such as plumbing, electrical wiring, escalators, and elevators.

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3 years ago
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faltersainse [42]
D. Speak your ideas with respect on the internet .
7 0
2 years ago
Assume we are testing a variable is_sunny in a while loop. is_sunny = “n”.
zubka84 [21]

Answer:

while(is_sunny=="n")

Explanation:

The loop keeps repeating itself until a certain condition is met.

Here while loop keeps executing until value of is_sunny is not equal to 'n'

When the value of is_sunny is not equal to n then the loop stops.

So lets explain this logic with a chunk of code:

#include <iostream> //to use input output functions

using namespace std; //to identify objects like cin cout

int main() {  //start of main function

  string is_sunny = "n"; //value of is_sunny is set to n

  cout<<"Enter value of is_sunny: "; // prompts user to enter value of is_sunny

  cin>>is_sunny; // reads value of is_sunny from user

  while(is_sunny=="n") // keeps iterating until value of is_sunny is not equal to n

  {   cout<<"keep executing until is_sunny is not equal to n"<<endl;//display this message with each iteration

      cout<<"Enter value of is_sunny: "; //keeps prompting to enter is_sunny

      cin>>is_sunny;   } } //keeps reading value of is_sunny from user

Now if the user keeps entering "n" as value of is_sunny then the loop keeps repeating. When the user enters any string other than n then the loop breaks. The output of the program is attached.

6 0
3 years ago
The following code is intended to calculate the sum of the first five positive odd integers. int sum = 0, k; for (k = 1; k &lt;=
goldfiish [28.3K]
Calculate the sum of the first 5 positive odd integers: Let's do this in our head first, so we can check if our code is right or not!

The first positive 5 odd integers are: 1, 3, 5, 7, 9
Sum these to: 25

int sum = 0, k; <------These just declare our variables, telling the program 'Hey, I'm going to use 'sum' and 'k' to store data.

for (k = 1; <---We're going to repeat the following code, and we're starting at 1
k <= 10; <---- We're going to continue to repeat until we greater than 10.
k += 2) <------ Every time we do a loop, we're going to add 2.

{ sum += k; } <---- We're going to increase the number inside "sum" by the number inside "k"

Let's run this and see what happens. Remember, we keep going until we hit more than 10.

Round 0: k = nothing, sum = 0 (before we start the loop)
Round 1: k = 1, sum = 1
Round 2: k = 3, sum = 1+3 or 4
Round 3: k = 5, sum = 4 + 5 or 9
Round 4: k = 7, sum = 9 + 7 = 16
Round 5: k = 9, sum = 16 + 9 = 25
Round 6: k = 11, sum = 25 + 11 = 36

Well, we can tell here that round 5 was correct, but round 6 is not correct. And our loop condition says <=10, which means we have to do Round 6.

This means we did it one too many times. Our ending condition should be <10, instead of <=10. 

Option B


5 0
3 years ago
Write a program that contains three methods:
Reil [10]

Answer:

#include <stdio.h>//defining header file

int max (int x, int y, int z) //defining a method max that hold three parameters

{

   if(x>=y && x>=z)//defining if block that checks x is greater then y and x is greater then z

   {

       return x;//return the value x

   }

   else if(y>z)//defining else if block it check y is greater then z

   {

       return y;//return the value y

   }

   else//else block

   {

       return z;//return the value z

   }

}

int min (int x, int y, int z) //defining a method max that holds three parameters

{

if(x<=y && x<=z) //defining if block that check x value is less then equal to y and less then equal to z

{

return x;//return the value of x

}

if(y<=x && y<=z) //defining if block that check y value is less then equal to x and less then equal to z

{

return y;//return the value of y

}

if(z<=x && z<=x)//defining if block that check z value is less then equal to x  

{

return z;//return the value of z

}

return x;//return the value of z  

}

int average (int x, int y, int z) //defining average method that take three parameters

{

int avg= (x+y+z)/3;//defining integer variable avg that calculate the average

return avg;//return avg value

}

int main()//defining main method

{

   int x,y,z;//defining integer variable

   printf("Enter first value: ");//print message

   scanf("%d",&x);//input value from the user end

   printf("Enter Second value: ");//print message

   scanf("%d",&y);//input value from the user end

   printf("Enter third value: ");//print message

   scanf("%d",&z);//input value from the user end

   printf("The maximum value is: %d\n", max(x,y,z));//calling the method max

   printf("The minimum value is: %d\n", min(x,y,z));//calling the method min

   printf("The average value is: %d\n", average(x,y,z));//calling the method average

   return 0;

}

Output:

Enter first value: 45

Enter Second value: 35

Enter third value: 10

The maximum value is: 45

The minimum value is: 10

The average value is: 30

Explanation:

In the above-given code, three methods "max, min, and average" is declared that holds three integer variable "x,y, and z" as a parameter and all the method work as their respective name.

  • In the max method, it uses a conditional statement to find the highest number among them.
  • In the min method, it also uses the conditional statement to find the minimum value from them.
  • In the average method, it defined an integer variable "avg" that holds the average value of the given parameter variable.
  • In the main method, three variable is defined that inputs the value from the user end and passes to the method and print its value.      
7 0
3 years ago
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