Assume we are testing a variable is_sunny in a while loop. is_sunny = “n”.
1 answer:
Answer:
while(is_sunny=="n")
Explanation:
The loop keeps repeating itself until a certain condition is met.
Here while loop keeps executing until value of is_sunny is not equal to 'n'
When the value of is_sunny is not equal to n then the loop stops.
So lets explain this logic with a chunk of code:
#include <iostream> //to use input output functions
using namespace std; //to identify objects like cin cout
int main() { //start of main function
string is_sunny = "n"; //value of is_sunny is set to n
cout<<"Enter value of is_sunny: "; // prompts user to enter value of is_sunny
cin>>is_sunny; // reads value of is_sunny from user
while(is_sunny=="n") // keeps iterating until value of is_sunny is not equal to n
{ cout<<"keep executing until is_sunny is not equal to n"<<endl;//display this message with each iteration
cout<<"Enter value of is_sunny: "; //keeps prompting to enter is_sunny
cin>>is_sunny; } } //keeps reading value of is_sunny from user
Now if the user keeps entering "n" as value of is_sunny then the loop keeps repeating. When the user enters any string other than n then the loop breaks. The output of the program is attached.
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Answer:
Explanation:
The following program was written in Java. It creates a loop that asks the user for numbers. If it can convert it to an integer it accepts it and adds it to the sum variable otherwise it ouputs that it is not a valid number. Once all 10 integers are added it prints the Average of the values entered.
import java.util.ArrayList;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int sum = 0;
while (count != 10) {
System.out.println("Enter a number: ");
String answer = in.nextLine();
try {
int intAnswer = Integer.parseInt(answer);
sum += intAnswer;
count += 1;
} catch (NumberFormatException e) {
System.out.println("Not a valid number.");
}
}
int average = sum / count;
System.out.println("Average: " + average);
}
}
