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2 years ago

The bill for lunch at a restaurant was $30. The dinner added 20% tip. Which equation relates the tip, t, with the bill, b?

Mathematics

2 answers:

77julia77 [94]2 years ago

8 0

Hi! :)

The answer is A, here's why:

When tipping at a restaurant, first you need to figure out how much you're tipping. You need to move the decimal left 2 places on how much you tip. So for 20%, you get .20

Then to figure out how much to tip for 20%, you would multiply that .20 by how much the bill was and that's your tip. So .20*30=6. Your tip should be 6 dollars, and the formula for that is t=.20<em>b</em>

tigry1 [53]2 years ago

7 0

A would be the answer to this problem. To find any tip, you usually calculate it by percentage . So to find the percentage of the bill, you multiply it by the percentage which is divided by 100. So A, t=0.20b would be the answer.

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What the slope and y intercept ? and how did you find it ?

EastWind [94]

Answer:

Slope: $m=4$

y-intercept: $b=-1$

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

The slope can be found with the following formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

In this case you can say that:

$y_2=-5\\y_1=11\\\\x_2=-1\\x_1=3$

Knowing this values you can substitute them into the formula and then evaluate, in order to find the slope. This is:

$m=\frac{-5-11}{-1-3}\\\\m=\frac{-16}{-4}\\\\m=4$

By definition, the line intersects the y-axis when the value of "x" is 0.

Notice in the table that when $x=0$ , $y=-1$

Therefore, the y-intercept is:

$b=-1$

7 0

3 years ago

Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx

uranmaximum [27]

Given the differential equation

$5t^3 \frac{dx}{dt} +2x-2=0$

The solution is as follows:

$5t^3 \frac{dx}{dt} +2x-2=0 \\ \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\ \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\ \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\ \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\ \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\ \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\ \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\ \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1$

3 0

2 years ago

Please HELP!!!!!!!!!

DaniilM [7]

Calculate the sum

5x - 10 + 7 = 65 - 20x + 32

Move terms

5x - 3 = 97 - 20x

Collect the like terms and calculate

5x + 20x = 97 +3

Divide both sides by 25

25x = 100

X= 4 ANSWER

I skipped some steps because it would be too long :/

Multiply parenthesis by 8

20x>8(4x - 5) -20

Calculate

20x>32x - 40 - 20

Move variable to the left

20x>32x-60

Collect like terms

20x - 32x > -60

Divide both sides by -12

-12x>-60

X<5 ANSWER

8 0

2 years ago

Y + 12 = -26 thank you if you answer me

tia_tia [17]

Answer:

-38

Step-by-step explanation:

1. Isolate y to one side.

y+12=-26

subtract 12 to both sides

y=-38

3 0

2 years ago

Read 2 more answers

A researcher believes that there is a difference in how cautious male stray cats and female stray cats are when approaching peop

Anika [276]

Answer:

The null hypothesis is that there is no difference in the mean number of male and female cats

H₀; μ₂ - μ₁ = 0

Step-by-step explanation:

The given parameters are;

The given percentage of male stray cat population = 50%

The given percentage of female stray cat population = 50%

The number of areas the researcher visits, n = 15

The number of stray male cats he finds = 11

The kind of test to be performed = Sign test

The significance level, α = 0.05

A) Therefore the null hypothesis is H₀; μ₂ - μ₁ = 0

The alternative hypothesis is Hₐ; μ₂ - μ₁ ≠ 0.

5 0

2 years ago