A ball is thrown into the air from a height of 9cm above the ground, and its height is given by S=128+32t-16t^2, where t is the
time in seconds
1) find the values of t that makes S=0.
2) Do both of the values of t have meaning for this application? Explain why
1 answer:
-16t² + 32t + 128 = 0
-16t² + 64t - 32t + 128 = 0
-16t(t - 4) - 32(t - 4)
(-16t - 32)(t - 4) = 0
-16t -32 = 0 t - 4 = 0
-16t = 32 t = 4
t = -2
t = -2 and t = 4 are the values that makes S = 0.
Yes, because if you apply either of these values alone, S will be 0.
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