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Lana71 [14]
3 years ago
11

X/3=y/8=z/5 và 2x+3y-z=50

Mathematics
2 answers:
garri49 [273]3 years ago
5 0

Answer:

i find the design and functionality very coonfusing and poorly done, voice mail messages will not play, endlessly loading, even tried reinstalling, doesn't help, update: seems to be that you have to force quit the app and then start it again in order to listen to any voice messages, that is a major flaw and why has this been going on for so many months that I've lost count yet no one at the mighty Microsoft corporation seems to be competent enough to fix this?

dexar [7]3 years ago
3 0
X=3/8×16
x=6

(x, y, z)=(6, 16, 10)

Hope my answer helped u :)

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Answer:

D. undefined

General Formulas and Concepts:

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                 \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Trig Derivative:                                                                                                       \displaystyle \frac{d}{dx}[sinu] = u'cosu

Derivatives of Parametrics:                                                                                   \displaystyle \frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}}

Step-by-step explanation:

<u>Step 1: Define</u>

\displaystyle \frac{dx}{dt} = 5

\displaystyle \frac{dy}{dt} = sin(t^2)

<u>Step 2: Differentiate</u>

  1. [x Derivative] Basic Power Rule:                                                                   \displaystyle \frac{d^2x}{dt^2} = 0
  2. [y Derivative] Trig Derivative [Chain Rule]:                                                 \displaystyle \frac{d^2y}{dt^2} = cos(t^2) \cdot \frac{d}{dt}[t^2]
  3. [y Derivative] Basic Power Rule:                                                                   \displaystyle \frac{d^2y}{dt^2} = cos(t^2) \cdot 2t^{2 - 1}
  4. [y Derivative] Simplify:                                                                                   \displaystyle \frac{d^2y}{dt^2} = 2tcos(t^2)
  5. [Derivative] Rewrite:                                                                                     \displaystyle \frac{d^2y}{dx^2} = \frac{2tcos(t^2)}{0}

Anything divided by 0 is undefined.

Topic: AP Calculus BC (Calculus I/II)

Unit: Differentiation with Parametrics

Book: College Calculus 10e

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