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natka813 [3]
3 years ago
5

En el acuario donde trabaja Alexandra, han requerido 4627 peces para distribuirlos en 21 peceras ¿cuantos peces se deben colocar

en casa una de las peceras? ¿ se hará necesario agregar una pecera más? ¿Cuantos peces colocarán en esa pecera?
Mathematics
1 answer:
brilliants [131]3 years ago
7 0

Answer: Se colocará 220 peces en cada pecera pero necesitaremos 1 pecera más para colocar los 7 peces restantes.

Step-by-step explanation:

4627/21=220.33....

21*220=4620

4627-4620=7 peces restantes en la última pecera

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serg [7]

Answer:

6 possible outcomes, 50% or 3/6 getting the racing bike, 2/6 or 1/3 being red, and 2/6 or 1/3 getting silver bike.

Step-by-step explanation:

                      racing bike                          mountain bike

                red   black   silver                   red   black   silver    

3 0
3 years ago
The expression 3x^3-5x^2+3x-1 has ___ terms and a constant of ____.
Andrews [41]
<span>The expression 3x^3-5x^2+3x-1 has ___ terms and a constant of ____.
have four terms and 1 constant
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5 0
4 years ago
Which function is graphed below?
GalinKa [24]

Answer:

f(x) = sin(x)

3 0
2 years ago
(Label each one)
shutvik [7]

1,3) no solution

2,4,5,6,7) solution

5 0
4 years ago
The number of violent crimes committed in a day possesses a distribution with a mean of 2.2 crimes per day and a standard deviat
VARVARA [1.3K]

Answer:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 2.2

\sigma_{\bar X}= \frac{6}{\sqrt{100}}= 0.6

Step-by-step explanation:

For this case we have the following info given:

\mu = 2.2 represent the mean

\sigma = 6 represent the deviation

We select a sample size of n=100. This sample is >30 so then we can use the central limit theorem. And we want to find the distribution for the sample mean and we know that the distribution is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 2.2

\sigma_{\bar X}= \frac{6}{\sqrt{100}}= 0.6

6 0
4 years ago
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