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Misha Larkins [42]

4 years ago

14

Create a table of data for two different linear functions. The table should use the same values of x for both functions. Based o

n your table, will the graphs of these two functions intersect? Explain your answer.

1 answer:

user100 [1]4 years ago

4 0

Answer:

Yes they will intersect

Function 1= F(X)=2X+5

Function 2=H(X)=3X+2

INTERSECT=(3,11)

Step-by-step explanation:

First of all, we create 2 LINEAR function, i created the function f(x)=2x+5 and the function h(x)=3x+2, both are linear(without a quadratic term). Then

you replace the x for a number:

Table 1 (F(X)=2X+5) Table 2 (H(X)=3X+2)

X=1----->Y=2+5=7 X=1------>Y=3·1+2=5

X=2---->Y=2·2+5=9 X=2----->Y=3·2+2=8

X=3---->Y=3·3+5=11 X=3----->Y=3·3+2=11

With both tables of data we can see that in the X=3/Y=11 point this two linear functions will intersect so the answer is that the two functions will intersect at (3,11)----->(X,Y)

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Gnom [1K]

Answer:

2,144.66 miles³

Step-by-step explanation:

v = (4/3)πr³

v = (4/3)π(8³)

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2,144.66 miles³

6 0

3 years ago

Read 2 more answers

Help me with Rational and Irrational!

Dafna1 [17]

Rational Numbers: Any number that can be expressed as a fraction or ratio that may contain repeating decimals, or terminating decimals.

Irrational Numbers: Any number that cannot be expressed as a fraction or ratio that has non-repeating non-terminating decimals.

With this information, sort the given values into one of each of these categories.

Cheers.

8 0

3 years ago

In triangle $ABC$, the angles $\angle A$, $\angle B$, $\angle C$ form an arithmetic sequence. If $\angle A = 23^\circ$, then wha

LenKa [72]

Answer:

$97^0$

Step-by-step explanation:

Given that the angles A, B, C in a Triangle form an arithmetic sequence where A=23 degrees.

The nth term of an Arithmetic sequence is given by the formula: $T_n=a+(n-1)d$

Where:

a=first term

n=number of term

d=common difference

In this case,

$Angle \:A, a=23^0$

$Angle B, T_2=23+(2-1)d=(23+d)^0\\Angle C, T_3=23+(3-1)d=(23+2d)^0$

The sum of angles in a triangle is 180 degrees. Therefore:

∠A+∠B+∠C=180 degrees

$23^0+(23+d)^0+(23+2d)^0=180\\69^0+3d=180^0\\3d=180^0-69^0\\3d=111^0\\d=37^0$

Therefore:

Angle C,

$(23+2d)^0=(23+2(37))^0=23+74\\C=97^0$

6 0

3 years ago

What will be the value of

madreJ [45]

The expression as given doesn't make much sense. I think you're trying to describe an infinitely nested radical. We can express this recursively by

$\begin{cases}a_1=\sqrt{42}\\a_n=\sqrt{42+a_{n-1}}\end{cases}$

Then you want to know the value of

$\displaystyle\lim_{n\to\infty}a_n$

if it exists.

To show the limit exists and that $a_n$ converges to some limit, we can try showing that the sequence is bounded and monotonic.

Boundedness: It's true that $a_1=\sqrt{42}\le\sqrt{49}=7$ . Suppose $a_k\le 7$ . Then $a_{k+1}=\sqrt{42+a_k}\le\sqrt{42+7}=7$ . So by induction, $a_n$ is bounded above by 7 for all $n$ .

Monontonicity: We have $a_1=\sqrt{42}$ and $a_2=\sqrt{42+\sqrt{42}}$ . It should be quite clear that $a_2>a_1$ . Suppose $a_k>a_{k-1}$ . Then $a_{k+1}=\sqrt{42+a_k}>\sqrt{42+a_{k-1}}=a_k$ . So by induction, $a_n$ is monotonically increasing.

Then because $a_n$ is bounded above and strictly increasing, the limit exists. Call it $L$ . Now,

$\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}a_{n-1}=L$

$\displaystyle\lim_{n\to\infty}a_n=\lim_{n\to\infty}\sqrt{42+a_{n-1}}=\sqrt{42+\lim_{n\to\infty}a_{n-1}}$

$\implies L=\sqrt{42+L}$

Solve for $L$ :

$L^2=42+L\implies L^2-L-42=(L-7)(L+6)=0\implies L=7$

We omit $L=-6$ because our analysis above showed that $L$ must be positive.

So the value of the infinitely nested radical is 7.

4 0

3 years ago

Help pls 2x^2+5x+3x+1

Oxana [17]

Answer: 2x^2+8x+1

Step-by-step explanation:

5x+3x=8x

4 0

3 years ago