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miskamm [114]
4 years ago
8

What would this be in expanded form 9,500?

Mathematics
2 answers:
Eva8 [605]4 years ago
6 0

Hello!

The answer will be 9000+500

We know that 9 is in the Thousands Place. So the 9 will become 9000.

We also know that 5 is in the Hundreds Place. So the 5 will become 500.

Due to the fact there are 0's in the Tens and Ones Place we will do anything with it because it won't add up anything. What I mean by add up is that it will keep the number the same as it is. So since the answer is 9000+500, 0 wont do anything.

disa [49]4 years ago
5 0

Answer:

9 thousand 5 hundred

Step-by-step explanation:

hope this helps

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C

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Based on the other answers. C is the odd one out.

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How many pounds are there in a 3 1/4 tons
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Step-by-step explanation:

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4 years ago
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ANSWER THREE THROUGH FIVE , ILL GIVE YOU BRAINLIST!!!
Ray Of Light [21]

Answer:

Step-by-step explanation:

3) diameter of penny = 19 mm

                          r = 19/2 = 9.5 mm

Area of penny = πr²

                        = 3.14 * 9.5 * 9.5

                         = 283.385

                         = 283.39 mm²

Diameter of nickel = 21 mm

                          r = 21/2 = 10.5 mm

Area of nickel  = πr²

                         = 3.14 * 10.5 *10.5

                        = 346.185

                        = 346.19 mm²

346.19 - 283.39 = 62.8 mm²

Area of Canadian nickel is greater than Canadian penny by 32.6 mm²

4)  r = 12 mm

Area of circle = πr²

                      = 3.14 * 12 * 12

                       =  452.16 mm²

5) r  = 20 cm

Area of circle =  πr²

                      = 3.14 * 20 * 20

                      = 1256 cm²

6 0
3 years ago
In 1985, the cost of clothing for a certain familiy was $620. In 1995, 10 years later, the cost of clothing for this famility wa
Sholpan [36]

Answer:

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Step-by-step explanation:

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First step is to calculate the amount that is increase per year

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Now let y be :38*x + $620 and let x be 6 years (1991-1985)

Second step is to calculate the cost of the clothing in 1991

y = 38*6 + 620

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Therefore the cost of this familiy's clothing in 1991 will be $848

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3 years ago
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(3+3i) - (13+15i)

=3+3i-13-15i
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