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Luba_88 [7]
3 years ago
11

What is the length of the longest possible laser beam he could send rounded to the nearest tenth of an inch?

Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0

Where is the diagram????????

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Dan will be 8X years next year. how old was Dan five years ago. give your answer in terms of X
morpeh [17]
If Dan is 8x years old next year then he must be 8x-1 years old this year
With the same logic, five years ago from this year, he must be 8x-1-5=8x-6

The answer should be 8x-6
6 0
3 years ago
Segment BD is a median. Solve for x. Round to the nearest tenth, if necessary. (Image not necessarily to scale.)
nata0808 [166]

Answer: 10

Step-by-step explanation:

By definition, the point at which a median intersects the side of the triangle opposite from the vertex from which it is drawn is the midpoint of that side.

6 0
2 years ago
2,5 m to 75 cm as ratio in its simplest form​
zhannawk [14.2K]

Answer:

10 : 3

Step-by-step explanation:

Convert one of the measurements so that it is in the same form as the other.  (Easiest to convert m to cms so we are not working with decimals)

2.5 m = 2.5 x 100 = 250 cm (since there are 100 cm in a meter)

Therefore, as a ratio:

250 : 75

We can divide both by 5:

50 : 15

We can further divide by 5:

10 : 3

(no further simplifying)

So 2.5 m to 75cm as a ratio is 10 : 3

4 0
3 years ago
If there are 360 g of radioactive material with a half life (decreased by half or 50% )of 1 hour, how much of the radioactive ma
Lostsunrise [7]

After 1 hour, 360 g decays to 180 g.

After another hour (total 2 hours), 180 g decays to 90 g.

After another hour (total 3), 90 g decays to 45 g.

After one more (total 4), 45 g decays to 22.5 g.

More quickly, with a half-life of 1 hour, the 360 g of starting material decays to

(360 g) / 2⁴ = 22.5 g

In general, if the half-life is 1 hour, then after <em>n</em> hours, an initial amount <em>A</em> of this substance decays according to

<em>A</em> / 2<em>ⁿ</em>

5 0
3 years ago
The mass of the sun is 2.13525×1030 kilograms. The mass of Mercury is 3.285×1023 kilograms. How many times greater is the mass o
Helga [31]
<span>6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.</span>
8 0
3 years ago
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