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3 years ago

What is the value of y if the segment outside the circle is tangent to the circle?

Mathematics

2 answers:

Dahasolnce [82]3 years ago

4 0

95 would be the correct answer.

Heres also the others

1) 31
2) 68
3) 28
4) 35
5) 95
6) 126

dem82 [27]3 years ago

3 0

Answer: B : 95°

Step-by-step explanation:

Since, the measurement of an angle formed by a chord and a tangent that intersect on a circle, is half the measure of the intercepted arc.

In the given diagram, the intercepted angle = 360° - 170° = 190°,

Hence, by the above definition,

$y=\frac{\text{Intercepted arc}}{2}$

$=\frac{190^{\circ}}{2}$

$=95^{\circ}$

Thus, the measurement of angle y = 95°

⇒ Option B is correct.

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Im not sure if anyone knows how to do this but if u do could u pleaseee help me with this!!!

slavikrds [6]

Answer:

y = -2x - 5

Step-by-step explanation:

1) Find the slope of the line.

The slope of the original line is the same as the slope of the parallel line.

Slope formula:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

In this case you can choose any 2 set of points on the table.

$m = \frac{4 - 2}{-3 - (-2)}$ = $\frac{4 - 2}{-3 + 2}$ = $\frac{2}{-1}$ = -2

So the slope of the line is -2

2) Use the point-slope formula to find the equation of the line.

Point-slope formula:

$y - y_{1} = m(x - x_{1})$

Now plug in the point (0, -5) and the slope -2 into the equation.

y - (-5) = -2(x - 0)

y + 5 = -2(x - 0)

To solve the equation first apply the distributive property.

y + 5 = -2x + 0

y + 5 = -2x

Next, subtract 5 from sides.

y = -2x - 5

You know have your equation in point-slope form!

6 0

3 years ago

Find the solution of the given initial value problem in explicit form. y′=(1−5x)y2, y(0)=−12 Enclose numerators and denominators

Nata [24]

Answer:

The solution is $y=-\frac{12}{12x-30x^2+1}$ .

Step-by-step explanation:

A first order differential equation $y'=f(x,y)$ is called a separable equation if the function $f(x,y)$ can be factored into the product of two functions of $x$ and $y$ :

$f(x,y)=p(x)h(y)$

where $p(x)$ and $h(y)$ are continuous functions.

We have the following differential equation

$y'=(1-5x)y^2, \quad y(0)=-12$

In the given case $p(x)=1-5x$ and $h(y)=y^2$ .

We divide the equation by $h(y)$ and move $dx$ to the right side:

$\frac{1}{y^2}dy\:=(1-5x)dx$

Next, integrate both sides:

$\int \frac{1}{y^2}dy\:=\int(1-5x)dx\\\\-\frac{1}{y}=x-\frac{5x^2}{2}+C$

Now, we solve for $y$

$-\frac{1}{y}=x-\frac{5x^2}{2}+C\\-\frac{1}{y}\cdot \:2y=x\cdot \:2y-\frac{5x^2}{2}\cdot \:2y+C\cdot \:2y\\-2=2yx-5yx^2+2Cy\\y\left(2x-5x^2+2C\right)=-2\\\\y=-\frac{2}{2x-5x^2+2C}$

We use the initial condition $y(0)=-12$ to find the value of C.

$-12=-\frac{2}{2\left(0\right)-5\left(0\right)^2+2C}\\-12=-\frac{1}{c}\\c=\frac{1}{12}$

Therefore,

$y=-\frac{2}{2x-5x^2+2(\frac{1}{12})}\\y=-\frac{12}{12x-30x^2+1}$

4 0

3 years ago

Need help tremendously

Alina [70]

basically since 30 minutes is half of an hour, to get to a full hour you can multiply by 2, so you do that for both, 2/3 included so you get 2/3 * 2/1 4/3 is 1 1/3

5 0

3 years ago

A rectangle is 7 meters. The perimeter is 24. What is the width?

lana [24]

P=2(L+W)
if length=7
and P=24
24=2(7+W)
divide both sdes by 2
12=7+W
minus 7both sides
5=W
width=5meters

7 0

3 years ago

Please help me with these problems :( -random person who struggles in pre algebra

yKpoI14uk [10]

Hope these help:
#9
a-4 divided by 5 = 12
5*12 is 60
60+4 is 64
60 (final answer for a)
#10
n+3 divided by 8 = -4
8*(-4) = -32
-32 + 3 = -35
-32 (final answer for n)
#11
6+z divided by 10 = -2
-2 * 10 = -20
-20=6=-26
-20 (final answer for z)
btw, can't see diagram

8 0

3 years ago