Martin puts two bowls of fruit out for his friends.The bowl of grapes has 9 green grapes and 16 red grapes. The bowl of tangerin es has 7 seeded and 3 seedless tangerines.
2 answers:
Answer:
27/250
Step-by-step explanation:
P(a green grape and a seedless tangerine)
=P(green grape) x P(seedless tangerine)
The bowl of grapes has 9 green grapes and 16 red grapes.
P(green grape)=green grapes / total grapes
=9/(9+16)
=9/25
The bowl of tangerines has 7 seeded and 3 seedless tangerines.
P(seedless tangerine)=seedless / total
=3/(3+7)
=3/10
P(a green grape and a seedless tangerine)
=9/25 x 3/10
=27/250
Answer:
Step-by-step explanation:
There are two requirements: a green grape and a seedless tangerine
For grapes, total number of grapes is 9+16 = 25 and 9 are green
Prob (green grape)=9/25
For tangerines, total number of tangerines is 7+3 = 10 and 3 are seedless
Prob (seedless tangerine)=3/10
Prob (a green grape and a seedless tangerine)=9/25*3/10
=27/250
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