Question

Martin puts two bowls of fruit out for his friends.The bowl of grapes has 9 green grapes and 16 red grapes. The bowl of tangerines has 7 seeded and 3 seedless tangerines.
Martin's friend chooses a random grape and a random tangerine. What is the probability that she chooses a green grape and a seedless tangerine?

Answer 1

Answer:

27/250

Step-by-step explanation:

P(a green grape and a seedless tangerine)

=P(green grape) x P(seedless tangerine)

The bowl of grapes has 9 green grapes and 16 red grapes.

P(green grape)=green grapes / total grapes

=9/(9+16)

=9/25

The bowl of tangerines has 7 seeded and 3 seedless tangerines.

P(seedless tangerine)=seedless / total

=3/(3+7)

=3/10

P(a green grape and a seedless tangerine)

=9/25 x 3/10

=27/250

Answer 2

Answer:

Step-by-step explanation:

There are two requirements: a green grape and a seedless tangerine

For grapes, total number of grapes is 9+16 = 25 and 9 are green

Prob (green grape)=9/25

For tangerines, total number of tangerines is 7+3 = 10 and 3 are seedless

Prob (seedless tangerine)=3/10

Prob (a green grape and a seedless tangerine)=9/25*3/10

=27/250