Ask question

Ask question

All categories

3 years ago

9

The speed at which a certain computer can access the internet is 2 megabytes per second. How fast is this in megabytes per hour.

2 answers:

brilliants [131]3 years ago

7 0

(2 things/sec) x (3600 sec/hour) = 7200 things/hour

Ainat [17]3 years ago

5 0

$Converting\ units:\\\\ 2\frac{megabytes}{second}\\\\ 1second=\frac{1}{3600}h\\\\ 2\frac{megabytes}{second}*\frac{1}{\frac{1}{3600}}=2\frac{megabytes}{second}*\frac{3600}{1}=7200\frac{megabytes}{second}\\\\If\ 1second=\frac{1}{3600}\ you\ must\ multiply\ 2*\frac{1}{3600}\ to\ convert\ 1\ second\\ into\ hour.$

You might be interested in

Zane performs the elementary row operation represented by R2-½R1 on matrix A.

UkoKoshka [18]

Answer:

[2 5 0]

[-7 -11/2 12]

Step-by-step explanation:

We want to perform elementary row operation represented by R2 - ½R1 on matrix A in the figure attached.

Now, matrix A is given as;

[2 5 0]

[-6 -3 12]

Now, R1 is row 1 = [2 5 0]

R2 is row 2 = [-6 -3 12]

Thus, R2 - ½R1 = [-6 -3 12] - ½[2 5 0]

This gives;

[-6 -3 12] - [1 5/2 0] = [-7 -11/2 12]

Now,[-7 -11/2 12] will be the new row 2 since it's just an elementary row operation we did on the Matrix A.

Thus, the new matrix is now;

[2 5 0]

[-7 -11/2 12]

5 0

3 years ago

Read 2 more answers

PRECAL TRIG <br> WILL MARK BRAINLIEST IF THEY RESPOND IN 5 MINS

dybincka [34]

Its A

Because

a

is

right

6 0

3 years ago

Use the cubic model y=3x^3 to find the value of y when x=8

GalinKa [24]

Answer:

Value of y is 1536.

Step-by-step explanation:

We have given an expression $y=3x^3$

We need to find the value of y when x=8

We will substitute the value of x as 8 in the given expression we get

$y=3(8)^3$

On simplification we get

$y=3(512)$

On further simplification we get:

$y=1536$

Hence, the required value that is the value of y is 1536

7 0

3 years ago

Read 2 more answers

What is the radius of this circle?

Vesna [10]

Answer:

C

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Felipe borrowed $8000 at a rate of 16.5%, compounded monthly. Assuming he makes no payments, how much will he owe after 7 years?

Gelneren [198K]

Answer:

$25,193.17

Explanation:

Given:

• Principal Felipe borrowed, P=$8000

,

• Annual Interest Rate, r=16.5%=0.165

,

• Compounding Period, k=12 (Monthly)

,

• Time, t=7 years

We want to determine how much he will owe after 7 years.

In order to carry out this calculation, use the compound interest formula below:

$A(t)=P\mleft(1+\frac{r}{k}\mright)^{tk}$

Substitute the values defined above:

$A(t)=8000\mleft(1+\frac{0.165}{12}\mright)^{12\times7}$

Finally, simplify and round to the nearest cent.

$\begin{gathered} A(t)=8000(1+0.01375)^{84} \\ =8000(1.01375)^{84} \\ =\$25,193.17 \end{gathered}$

After 7 years, Felipe will owe $25,193.17.

3 0

1 year ago